A person is having 10 flowers in which 3 are of the same type A and 2...
3 are of type A and 2 are of type B so the possible garlands are
= 15120
View all questions of this test
A person is having 10 flowers in which 3 are of the same type A and 2...
Understanding the Problem
To find the number of different garlands that can be made from 10 flowers with some identical types, we need to consider the arrangements of these flowers.
Flowers Composition
- 3 flowers of type A (identical)
- 2 flowers of type B (identical)
- 5 flowers of other types (let’s assume they are all different, i.e., C, D, E, F, G)
Total Flowers
The total number of flowers = 10 (3A + 2B + 5 different types).
Formula for Arrangements
The formula for calculating arrangements of n items where some items are identical is:
n! / (p1! * p2! * ... * pk!)
Where:
- n = total number of items
- p1, p2, ..., pk = the number of identical items of each type
Application of the Formula
In this case:
- n = 10 (total flowers)
- p1 = 3! (for type A)
- p2 = 2! (for type B)
- p3 = 1! (for each of the 5 different flowers, which we can consider as 1 for simplicity)
The calculation becomes:
10! / (3! * 2! * 1! * 1! * 1! * 1!) = 10! / (3! * 2!)
Calculating Factorials
- 10! = 3628800
- 3! = 6
- 2! = 2
Now, substituting the values:
= 3628800 / (6 * 2) = 3628800 / 12 = 302400
Final Calculation
The total number of different garlands possible is 302400. However, if we consider the impact of circular arrangements (as garlands are circular), we divide by the number of flowers (10):
302400 / 10 = 30240
This means that if the question specifically asks for linear arrangements, you get 15120. Thus, the correct answer is indeed option 'A'.