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Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.
[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]
How many collisions can occur in the hash table?
- a)8
- b)12
- c)13
- d)10
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash t...
23 ⇒ No collision
13 ⇒ No collision
21 ⇒ No collision
14 ⇒ 1 collision
7 ⇒ 2 collisions
7%7 = 1 (Collision)
[(7%7) + 1] mod 7 = 1 (Collision)
[(7%7) + 4] mod 7 = 4
Similarly, 8 ⇒ 2 collisions
15 ⇒ 3 collisions.
Therefore, total collisions are: 1 + 2 + 2 + 3= 8
Most Upvoted Answer
Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash t...
Solution:
Hash Table Size = 7
Hash Function h(key) = key % 7
Quadratic Probing c(i) = ±i^2
Load the keys 23, 13, 21, 14, 7, 8, and 15 in the hash table using quadratic probing.
1. Insert Key 23
h(key) = 23 % 7 = 2
h_0(key) = (23 + 0^2) % 7 = 2
Insert 23 in Hash Table at index 2.
2. Insert Key 13
h(key) = 13 % 7 = 6
h_0(key) = (13 + 0^2) % 7 = 6
Insert 13 in Hash Table at index 6.
3. Insert Key 21
h(key) = 21 % 7 = 0
h_0(key) = (21 + 0^2) % 7 = 0
Insert 21 in Hash Table at index 0.
4. Insert Key 14
h(key) = 14 % 7 = 0
h_0(key) = (14 + 0^2) % 7 = 0
h_1(key) = (14 + 1^2) % 7 = 2
Insert 14 in Hash Table at index 2.
5. Insert Key 7
h(key) = 7 % 7 = 0
h_0(key) = (7 + 0^2) % 7 = 0
h_1(key) = (7 + 1^2) % 7 = 1
h_2(key) = (7 + 2^2) % 7 = 2
h_3(key) = (7 + 3^2) % 7 = 5
Insert 7 in Hash Table at index 5.
6. Insert Key 8
h(key) = 8 % 7 = 1
h_0(key) = (8 + 0^2) % 7 = 1
h_1(key) = (8 + 1^2) % 7 = 4
h_2(key) = (8 + 2^2) % 7 = 0
h_3(key) = (8 + 3^2) % 7 = 4
h_4(key) = (8 + 4^2) % 7 = 3
Insert 8 in Hash Table at index 3.
7. Insert Key 15
h(key) = 15 % 7 = 1
h_0(key) = (15 + 0^2) % 7 = 1
h_1(key) = (15 + 1^2) % 7 = 2
h_2(key) = (15 + 2^2) % 7 = 0
h_3(key) = (15 + 3^2) % 7 = 4
h_4(key) = (15 + 4^2) % 7 = 6
h_5(key) = (15 + 5^2) % 7 = 5
h_6(key) = (15 +
Hash Table Size = 7
Hash Function h(key) = key % 7
Quadratic Probing c(i) = ±i^2
Load the keys 23, 13, 21, 14, 7, 8, and 15 in the hash table using quadratic probing.
1. Insert Key 23
h(key) = 23 % 7 = 2
h_0(key) = (23 + 0^2) % 7 = 2
Insert 23 in Hash Table at index 2.
2. Insert Key 13
h(key) = 13 % 7 = 6
h_0(key) = (13 + 0^2) % 7 = 6
Insert 13 in Hash Table at index 6.
3. Insert Key 21
h(key) = 21 % 7 = 0
h_0(key) = (21 + 0^2) % 7 = 0
Insert 21 in Hash Table at index 0.
4. Insert Key 14
h(key) = 14 % 7 = 0
h_0(key) = (14 + 0^2) % 7 = 0
h_1(key) = (14 + 1^2) % 7 = 2
Insert 14 in Hash Table at index 2.
5. Insert Key 7
h(key) = 7 % 7 = 0
h_0(key) = (7 + 0^2) % 7 = 0
h_1(key) = (7 + 1^2) % 7 = 1
h_2(key) = (7 + 2^2) % 7 = 2
h_3(key) = (7 + 3^2) % 7 = 5
Insert 7 in Hash Table at index 5.
6. Insert Key 8
h(key) = 8 % 7 = 1
h_0(key) = (8 + 0^2) % 7 = 1
h_1(key) = (8 + 1^2) % 7 = 4
h_2(key) = (8 + 2^2) % 7 = 0
h_3(key) = (8 + 3^2) % 7 = 4
h_4(key) = (8 + 4^2) % 7 = 3
Insert 8 in Hash Table at index 3.
7. Insert Key 15
h(key) = 15 % 7 = 1
h_0(key) = (15 + 0^2) % 7 = 1
h_1(key) = (15 + 1^2) % 7 = 2
h_2(key) = (15 + 2^2) % 7 = 0
h_3(key) = (15 + 3^2) % 7 = 4
h_4(key) = (15 + 4^2) % 7 = 6
h_5(key) = (15 + 5^2) % 7 = 5
h_6(key) = (15 +
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Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer?
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Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer?.
Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer?.
Solutions for Load the keys 23, 13, 21, 14, 7, 8, and 15 in this order, in a hash table of size 7 using quadratic probing with c(i)= ±i^2 the hash function h(key) = key % 7.[Note: The required probe sequences are given by: h_i (key)= (h(key)±i^2 )%7,i=0,1,2,3,....]How many collisions can occur in the hash table?a)8b)12c)13d)10Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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