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The two functional groups characteristic of sugars are    [2018]
  • a)
    Hydroxyl and methyl
  • b)
    Carbonyl and methyl
  • c)
    Carbonyl and phosphate
  • d)
    Carbonyl and hydroxyl
Correct answer is option 'D'. Can you explain this answer?
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The two functional groups characteristic of sugars are [2018]a)Hydrox...
Carbohydrates (commonly called sugars) are chemically defined as polyhydroxy aldehyde or ketones. All sugar molecules have one carbonyl group (-CO-) in addition to hydroxyl group (OH) on other carbon atoms.
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The two functional groups characteristic of sugars are [2018]a)Hydrox...
Functional Groups in Sugars

Sugars are a class of biomolecules that are important sources of energy for living organisms. They are made up of carbon, hydrogen, and oxygen atoms arranged in a specific way. There are two functional groups that are characteristic of sugars:

1. Carbonyl Group

The carbonyl group is a functional group that consists of a carbon atom double bonded to an oxygen atom (C=O). In sugars, this group can be found in two forms:

- Ketose sugars have a carbonyl group in the middle of the molecule.
- Aldose sugars have a carbonyl group at the end of the molecule.

2. Hydroxyl Group

The hydroxyl group is a functional group that consists of an oxygen atom bonded to a hydrogen atom (OH). Sugars have multiple hydroxyl groups that are attached to the carbon atoms of the molecule.

Characteristic Functional Groups

The two functional groups that are characteristic of sugars are:

1. Carbonyl Group

- Aldose sugars have a carbonyl group at the end of the molecule.
- Ketose sugars have a carbonyl group in the middle of the molecule.

2. Hydroxyl Group

- Sugars have multiple hydroxyl groups that are attached to the carbon atoms of the molecule.

Answer

The correct answer is option D, carbonyl and hydroxyl groups.
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The two functional groups characteristic of sugars are [2018]a)Hydroxyl and methylb)Carbonyl and methylc)Carbonyl and phosphated)Carbonyl and hydroxylCorrect answer is option 'D'. Can you explain this answer?
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