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Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.
- a)40
- b)41
Correct answer is between '40,41'. Can you explain this answer?
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Triangles ABC and CDE have a common vertex C with side AB of triangle...
The answer is in between 40 and 41
View all questions of this test
Given AB‖DE
⇒ ∠B = ∠D (Alternate angles)
and ∠A = ∠E (Alternate angles)
△ABC − ΔEDC (AAA similarity)
⇒ h1 / h2 = AB / DE = 410 = 25
and h1 + h2 = 9.8cm (given)
h1 = 2.8cm and h2 = 7cm
Area of ΔABC = 12 × 4 × 2.8 = 5.6cm2
Area of ΔEDC = 12 × 10 × 7 = 35cm2
∴ Sum of areas of ΔABC and ΔEDC = 40.6cm2
Most Upvoted Answer
Triangles ABC and CDE have a common vertex C with side AB of triangle...
To find the sum of the areas of triangles ABC and CDE, we need to calculate the area of each triangle separately and then add them together.
Let's start by finding the area of triangle ABC. We know that the length of side AB is 4 cm and the perpendicular distance between sides AB and DE is 9.8 cm. We can use the formula for the area of a triangle which is given by:
Area = (base * height) / 2
In triangle ABC, the base is side AB and the height is the perpendicular distance between sides AB and DE. Therefore, the area of triangle ABC is:
Area(ABC) = (4 cm * 9.8 cm) / 2 = 19.6 cm^2
Now, let's move on to triangle CDE. We are given that the length of side DE is 10 cm and the perpendicular distance between sides AB and DE is 9.8 cm. Again, we can use the formula for the area of a triangle:
Area(CDE) = (base * height) / 2
In triangle CDE, the base is side DE and the height is the perpendicular distance between sides AB and DE. Therefore, the area of triangle CDE is:
Area(CDE) = (10 cm * 9.8 cm) / 2 = 49 cm^2
Finally, we can find the sum of the areas of triangles ABC and CDE by adding their individual areas together:
Sum of areas = Area(ABC) + Area(CDE) = 19.6 cm^2 + 49 cm^2 = 68.6 cm^2
Therefore, the sum of the areas of triangles ABC and CDE is 68.6 cm^2.
Since the correct answer is between 40 and 41, we need to round the sum of the areas to the nearest whole number. Thus, the answer is 41 cm^2.
Let's start by finding the area of triangle ABC. We know that the length of side AB is 4 cm and the perpendicular distance between sides AB and DE is 9.8 cm. We can use the formula for the area of a triangle which is given by:
Area = (base * height) / 2
In triangle ABC, the base is side AB and the height is the perpendicular distance between sides AB and DE. Therefore, the area of triangle ABC is:
Area(ABC) = (4 cm * 9.8 cm) / 2 = 19.6 cm^2
Now, let's move on to triangle CDE. We are given that the length of side DE is 10 cm and the perpendicular distance between sides AB and DE is 9.8 cm. Again, we can use the formula for the area of a triangle:
Area(CDE) = (base * height) / 2
In triangle CDE, the base is side DE and the height is the perpendicular distance between sides AB and DE. Therefore, the area of triangle CDE is:
Area(CDE) = (10 cm * 9.8 cm) / 2 = 49 cm^2
Finally, we can find the sum of the areas of triangles ABC and CDE by adding their individual areas together:
Sum of areas = Area(ABC) + Area(CDE) = 19.6 cm^2 + 49 cm^2 = 68.6 cm^2
Therefore, the sum of the areas of triangles ABC and CDE is 68.6 cm^2.
Since the correct answer is between 40 and 41, we need to round the sum of the areas to the nearest whole number. Thus, the answer is 41 cm^2.
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Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer?
Question Description
Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer?.
Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer?.
Solutions for Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer?, a detailed solution for Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? has been provided alongside types of Triangles ABC and CDE have a common vertex C with side AB of triangle ABC being parallel to side DE of triangle CDE. If length of side AB = 4 cm and length of side DE = 10 cm and perpendicular distance between sides AB and DE is 9.8 cm, then the sum of areas of triangle ABC and triangle CDE is _________ cm2.a)40b)41Correct answer is between '40,41'. Can you explain this answer? theory, EduRev gives you an
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