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The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer?.

Solutions for The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The orange box in the below figure consists of a minimum complexity circuit that uses only AND, OR and NOT gates. The function f(x,y,z) = 1 where any of the following conditions are satisfied : x is not equal to y and z is grounded y is equal to z , and x is set low x is equal to y , y is equal to z but x not equal to zThen which of the following equations leads to correct design for the minimum complexity circuit:a)xy + xyb)x + yzc)yz + xyd)yz + xyCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice GATE tests.