Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relationa)A + 3I + 2A-1=0b)A2 + 2A + 2I = 0c)(A + I) (A + I) = 0d)exp (A) = 0Correct answer is option 'A'. Can you explain this answer?

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Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix

A satisfies the relation

a)
A + 3I + 2A^-1=0
b)
A² + 2A + 2I = 0
c)
(A + I) (A + I) = 0
d)
exp (A) = 0

Correct answer is option 'A'. Can you explain this answer?

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Cayley-Hamilton Theorem states that a square matrix satisfies its own...

Characteristic equation is given by, , | A - λ | = 0

As Cayley-Hamilton Theorem states, a square matrix satisfies this equation, then,

A² + 3A + 2I = 0

Multiplying A^–1 to both sides, we get

⇒ ? + 3? + 2? ⁻¹ = 0

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Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relationa)A + 3I + 2A-1=0b)A2 + 2A + 2I = 0c)(A + I) (A + I) = 0d)exp (A) = 0Correct answer is option 'A'. Can you explain this answer?

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Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relationa)A + 3I + 2A-1=0b)A2 + 2A + 2I = 0c)(A + I) (A + I) = 0d)exp (A) = 0Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relationa)A + 3I + 2A-1=0b)A2 + 2A + 2I = 0c)(A + I) (A + I) = 0d)exp (A) = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cayley-Hamilton Theorem states that a square matrix satisfies its own characteristic equation. Consider a matrix A satisfies the relationa)A + 3I + 2A-1=0b)A2 + 2A + 2I = 0c)(A + I) (A + I) = 0d)exp (A) = 0Correct answer is option 'A'. Can you explain this answer?.

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