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Husband and wife apply for two vacancies that arise in a private company. Two friends apply for that position. If the probability of 1st friend's selection and 2nd friend's selection are 3/5 and 1/6 respectively,
Find the probability of both friends getting rejected.
  • a)
    3/5
  • b)
    1/4
  • c)
    2/7
  • d)
    1/3
Correct answer is option ''. Can you explain this answer?
Verified Answer
Husband and wife apply for two vacancies that arise in a private comp...
Probability of 1st friend's selection is 3/5
Probability of 1st friend's rejection is (1-3/5)=2/5
Probability of 2nd friend's selection is 1/6
Probability of 2nd friend's rejection is 1-1/6=5/6
probability of both friends get rejected is (2/5)×(5/6)=1/3
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Most Upvoted Answer
Husband and wife apply for two vacancies that arise in a private comp...
Probability of Selection for Friends:
- Probability of 1st friend's selection = 3/5
- Probability of 2nd friend's selection = 1/6

Finding Probability of Rejection:
To find the probability of both friends getting rejected, we need to find the probability of both of them not being selected.
- Probability of 1st friend not being selected = 1 - 3/5 = 2/5
- Probability of 2nd friend not being selected = 1 - 1/6 = 5/6

Probability of Both Friends Getting Rejected:
- Probability of both friends getting rejected = Probability of 1st friend not being selected * Probability of 2nd friend not being selected
- Probability of both friends getting rejected = (2/5) * (5/6) = 1/3
Therefore, the probability of both friends getting rejected is 1/3, which corresponds to option 'd'.
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Husband and wife apply for two vacancies that arise in a private company. Two friends apply for that position. If the probability of 1st friend's selection and 2nd friend's selection are 3/5 and 1/6 respectively,Find the probability of both friends getting rejected.a)3/5b)1/4c)2/7d)1/3Correct answer is option ''. Can you explain this answer?
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