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Consider the following program for an INTEL 8085 microprocessor
1) MVI A, 92 H
2) ORA A
3) JP PORT
4) XRI 66 H
5) PORT OUT F2 H
6) HLT
The content of output port F2 H after execution of the program is
  • a)
    F2 H
  • b)
    F4 H
  • c)
    0B H
  • d)
    0D H
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider the following program for an INTEL 8085 microprocessor1) MVI ...
1) A = 92H
2) A = 92H Parity flag = 0
3) Checks for parity
4) A = 92 ⊕ 66 = F4H
5) Send the content of accumulator to port F2H
⇒ Content of output port F2 H = F4
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Most Upvoted Answer
Consider the following program for an INTEL 8085 microprocessor1) MVI ...
Explanation:

The given program executes on an INTEL 8085 microprocessor. Let's understand the program line by line.

1) MVI A, 92 H

- MVI A is an instruction to move an 8-bit immediate value into the accumulator A.
- Here, the immediate value is 92 H (i.e., 1001 0010 in binary).
- So, after this instruction, the accumulator A will have the value 92 H.

2) ORA A

- ORA A is an instruction to perform a logical OR operation between the accumulator A and itself.
- This means that the accumulator A remains unchanged, and the zero flag (Z) is set to 1 if the result is zero, else set to 0.

3) JP PORT

- JP is a conditional jump instruction that transfers control to the specified address if the condition is true.
- Here, the condition is not specified, so it is a simple jump instruction.
- The target address is PORT, which is not specified in the program. So, it will jump to an unknown address, resulting in unpredictable behavior.

4) XRI 66 H

- XRI is an instruction to perform an exclusive OR operation between the accumulator A and the immediate value.
- Here, the immediate value is 66 H (i.e., 0110 0110 in binary).
- So, after this instruction, the accumulator A will have the value F4 H (i.e., 1111 0100 in binary).

5) PORT OUT F2 H

- PORT OUT is an instruction to output the value of the accumulator A to the specified output port.
- Here, the output port is F2 H (i.e., port number 242 in decimal).
- So, the value of the accumulator A (i.e., F4 H) will be outputted to port number 242.

6) HLT

- HLT is an instruction to halt the execution of the program.

Therefore, the content of output port F2 H after execution of the program is F4 H (i.e., the value of the accumulator A).
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Consider the following program for an INTEL 8085 microprocessor1) MVI A, 92 H2) ORA A3) JP PORT4) XRI 66 H5) PORT OUT F2 H6) HLTThe content of output port F2 H after execution of the program isa)F2 Hb)F4 Hc)0B Hd)0D HCorrect answer is option 'B'. Can you explain this answer?
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Consider the following program for an INTEL 8085 microprocessor1) MVI A, 92 H2) ORA A3) JP PORT4) XRI 66 H5) PORT OUT F2 H6) HLTThe content of output port F2 H after execution of the program isa)F2 Hb)F4 Hc)0B Hd)0D HCorrect answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider the following program for an INTEL 8085 microprocessor1) MVI A, 92 H2) ORA A3) JP PORT4) XRI 66 H5) PORT OUT F2 H6) HLTThe content of output port F2 H after execution of the program isa)F2 Hb)F4 Hc)0B Hd)0D HCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following program for an INTEL 8085 microprocessor1) MVI A, 92 H2) ORA A3) JP PORT4) XRI 66 H5) PORT OUT F2 H6) HLTThe content of output port F2 H after execution of the program isa)F2 Hb)F4 Hc)0B Hd)0D HCorrect answer is option 'B'. Can you explain this answer?.
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