For common emitter input characteristics VCE is 6V and VBE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept VCE constant.Correct answer is '24'. Can you explain this answer?

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For common emitter input characteristics V_CE is 6V and V_BE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept V_CE constant.

Correct answer is '24'. Can you explain this answer?

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For common emitter input characteristics VCE is 6V and VBE is changed...

To calculate input impedance we need to calculate h – parameter.

h_ei = ΔV_BE/ΔI_B|V_CE = 6V,

Constant = 0.48V /20μA = 24KΩ

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For common emitter input characteristics VCE is 6V and VBE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept VCE constant.Correct answer is '24'. Can you explain this answer?

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For common emitter input characteristics VCE is 6V and VBE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept VCE constant.Correct answer is '24'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For common emitter input characteristics VCE is 6V and VBE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept VCE constant.Correct answer is '24'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For common emitter input characteristics VCE is 6V and VBE is changed from 0.32 to 0.8V also base current changes from 40μA to 60μA, then by using the given data calculate the input impedance (in KΩ) kept VCE constant.Correct answer is '24'. Can you explain this answer?.

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