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A 700 mW maximum power dissipation diode at 25 °C has 5 mW/oC de-rating factor. If the forward voltage drop remains constant at 0.7 V, the maximum forward current at 65 °C is
  • a)
    700 mA
  • b)
    714 mA
  • c)
    1 A
  • d)
    1 mA
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 700 mW maximum power dissipation diode at 25 °C has 5 mW/oC de-r...
Power derating factor dW/dt = -5m W / °C
So power available at 65°C
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Most Upvoted Answer
A 700 mW maximum power dissipation diode at 25 °C has 5 mW/oC de-r...
Given data:
- Maximum power dissipation: 700 mW
- De-rating factor: 5 mW/oC
- Forward voltage drop: 0.7 V
- Maximum temperature: 65 °C

Calculations:
- Maximum power dissipation at 65 °C = Maximum power dissipation at 25 °C + (Temperature difference * De-rating factor)
- Maximum power dissipation at 65 °C = 700 mW + (40 * 5 mW/oC) = 900 mW
- Maximum forward current = Maximum power dissipation / Forward voltage drop
- Maximum forward current at 65 °C = 900 mW / 0.7 V = 1285.71 mA ≈ 1286 mA

Answer:
Therefore, the maximum forward current at 65 °C is 1286 mA which is closest to option 'B' (714 mA).
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