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Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer?.

Solutions for Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Answer the following questionbased on the given paragraph.Stability of carbocation, alkylfree radical and alkene can be explained on the basis of hyperconjugation.In all these cases, there is presence ofhydrogen atom at theadjacent carbon atom ofsp2hybridised carbon atom. Total number of hyperconjugating structures depends upon the number of hydrogen atoms present at adjacent carbon atom of sp2 C-atom.More the hyperconjugating structures, more is the stabihty of the ion.Decreasingorder of stabilityof following alkenes is(i) CH3 - CH = CH2(ii) CH3 - CH = CH - CH3(iii)(iv)a)(i) > (ii) > (iii) > (iv)b)(iv) > (iii) > (ii) > (i)c)(iii)>(ii)>(i)>(iv)d)(ii) > (iii) > (iv) > (i)Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.