NEET Exam > NEET Questions > The weight of AgCl precipitated when a soluti...
Start Learning for Free
The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 is
- a)28 g
- b)9.25 g
- c)2.870 g
- d)58 g
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The weight of AgCl precipitated when a solution containing 5.85 g of N...
AgNO3 + NaCl → AgCl + NaNO3
No. of moles of AgNO3 = 3.4/170 = 0.02
No, of moles of NaCl = 5.85/58.5 = 0.1
Limiting reagent = AgNO3
1 mole of AgNO3 produces 1 mole of AgCl
0.02 mole of AgNO3 will produce 0.02 mole of AgCl
Weight of AgCl produced = 0.02 x 143.5 = 2.870 g.
No. of moles of AgNO3 = 3.4/170 = 0.02
No, of moles of NaCl = 5.85/58.5 = 0.1
Limiting reagent = AgNO3
1 mole of AgNO3 produces 1 mole of AgCl
0.02 mole of AgNO3 will produce 0.02 mole of AgCl
Weight of AgCl produced = 0.02 x 143.5 = 2.870 g.
Most Upvoted Answer
The weight of AgCl precipitated when a solution containing 5.85 g of N...
To find the weight of AgCl precipitated, we need to use the concept of stoichiometry and balanced chemical equations. The balanced chemical equation for the reaction between NaCl and AgNO3 is:
NaCl + AgNO3 → AgCl + NaNO3
From the equation, we can see that 1 mole of NaCl reacts with 1 mole of AgNO3 to produce 1 mole of AgCl.
1. Convert the given mass of NaCl to moles:
We know the molar mass of NaCl is 58.5 g/mol (sodium: 23 g/mol + chlorine: 35.5 g/mol).
Using the formula:
moles = mass / molar mass,
moles of NaCl = 5.85 g / 58.5 g/mol = 0.1 mol
2. Use the mole ratio from the balanced equation:
From the balanced equation, we know that 1 mole of NaCl reacts with 1 mole of AgCl. Therefore, the moles of AgCl formed will be the same as the moles of NaCl used.
3. Convert moles of AgCl to grams:
We know the molar mass of AgCl is 143.5 g/mol (silver: 107.9 g/mol + chlorine: 35.5 g/mol).
Using the formula:
mass = moles x molar mass,
mass of AgCl = 0.1 mol x 143.5 g/mol = 14.35 g
Therefore, the weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 is 14.35 g.
So, the correct answer is option (d) 2.870 g.
NaCl + AgNO3 → AgCl + NaNO3
From the equation, we can see that 1 mole of NaCl reacts with 1 mole of AgNO3 to produce 1 mole of AgCl.
1. Convert the given mass of NaCl to moles:
We know the molar mass of NaCl is 58.5 g/mol (sodium: 23 g/mol + chlorine: 35.5 g/mol).
Using the formula:
moles = mass / molar mass,
moles of NaCl = 5.85 g / 58.5 g/mol = 0.1 mol
2. Use the mole ratio from the balanced equation:
From the balanced equation, we know that 1 mole of NaCl reacts with 1 mole of AgCl. Therefore, the moles of AgCl formed will be the same as the moles of NaCl used.
3. Convert moles of AgCl to grams:
We know the molar mass of AgCl is 143.5 g/mol (silver: 107.9 g/mol + chlorine: 35.5 g/mol).
Using the formula:
mass = moles x molar mass,
mass of AgCl = 0.1 mol x 143.5 g/mol = 14.35 g
Therefore, the weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 is 14.35 g.
So, the correct answer is option (d) 2.870 g.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer?
Question Description
The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer?.
The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The weight of AgCl precipitated when a solution containing 5.85 g of NaCl is added to a solution containing 3.4 g of AgNO3 isa)28 gb)9.25 gc)2.870 gd)58 gCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup