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How much oxygen is required for complete combustion of 560 g of ethene?
- a)6.4 kg
- b)1.92 kg
- c)2.8 kg
- d)9.6 kg
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
How much oxygen is required for complete combustion of 560 g of ethene...
28 g of C2H4 requires 96 g of O2
560 g of C2H4 requires 96/28 x 560
= 1920 g or 1.92 kg of O2
Most Upvoted Answer
How much oxygen is required for complete combustion of 560 g of ethene...
To solve this problem, we need to balance the chemical equation for the combustion of ethene:
C2H4 + O2 → CO2 + H2O
From the balanced equation, we can see that 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water.
First, we need to find the number of moles of ethene in 560 g.
Molar mass of ethene (C2H4) = 2(12.01) + 4(1.01) = 28.05 g/mol
Number of moles of ethene = 560 g / 28.05 g/mol = 19.96 mol
Next, we can use the stoichiometry of the balanced equation to find the number of moles of oxygen required.
1 mol C2H4 requires 3 mol O2
19.96 mol C2H4 requires 3 x 19.96 mol O2 = 59.88 mol O2
Finally, we can convert the number of moles of oxygen to mass.
Molar mass of oxygen (O2) = 2(16.00) = 32.00 g/mol
Mass of oxygen required = 59.88 mol O2 x 32.00 g/mol = 1916.16 g = 1.92 kg
Therefore, the correct answer is option B, 1.92 kg of oxygen is required for complete combustion of 560 g of ethene.
C2H4 + O2 → CO2 + H2O
From the balanced equation, we can see that 1 mole of ethene reacts with 3 moles of oxygen to produce 2 moles of carbon dioxide and 2 moles of water.
First, we need to find the number of moles of ethene in 560 g.
Molar mass of ethene (C2H4) = 2(12.01) + 4(1.01) = 28.05 g/mol
Number of moles of ethene = 560 g / 28.05 g/mol = 19.96 mol
Next, we can use the stoichiometry of the balanced equation to find the number of moles of oxygen required.
1 mol C2H4 requires 3 mol O2
19.96 mol C2H4 requires 3 x 19.96 mol O2 = 59.88 mol O2
Finally, we can convert the number of moles of oxygen to mass.
Molar mass of oxygen (O2) = 2(16.00) = 32.00 g/mol
Mass of oxygen required = 59.88 mol O2 x 32.00 g/mol = 1916.16 g = 1.92 kg
Therefore, the correct answer is option B, 1.92 kg of oxygen is required for complete combustion of 560 g of ethene.
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How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer?
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How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer?.
How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much oxygen is required for complete combustion of 560 g of ethene?a)6.4 kgb)1.92 kgc)2.8 kgd)9.6 kgCorrect answer is option 'B'. Can you explain this answer?.
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