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How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?
  • a)
    11.79 g
  • b)
    15.38 g
  • c)
    10.81 g
  • d)
    25.35 g
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
How much mass of sodium acetate is required to make 250 mL of 0.575 mo...
To calculate the mass of sodium acetate required to make a 0.575 M aqueous solution, we can use the formula:

Molarity (M) = moles of solute / volume of solution in liters

First, we need to convert the volume of the solution from milliliters to liters:

250 mL = 250/1000 = 0.25 L

Next, we rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution in liters

Given that the molarity is 0.575 M and the volume is 0.25 L, we can substitute these values into the formula:

moles of solute = 0.575 M x 0.25 L = 0.14375 moles

The molar mass of sodium acetate (NaC2H3O2) is calculated as follows:

Na: 1 atom x 22.99 g/mol = 22.99 g/mol
C: 2 atoms x 12.01 g/mol = 24.02 g/mol
H: 3 atoms x 1.01 g/mol = 3.03 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol

Total molar mass = 22.99 + 24.02 + 3.03 + 32.00 = 82.04 g/mol

Finally, we can calculate the mass of sodium acetate required using the moles of solute and the molar mass:

mass of sodium acetate = moles of solute x molar mass
mass of sodium acetate = 0.14375 moles x 82.04 g/mol = 11.79 g

Therefore, the correct answer is option A) 11.79 g.
Free Test
Community Answer
How much mass of sodium acetate is required to make 250 mL of 0.575 mo...
Molar mass of sodium acetate (CH3COONa)
= 82.0245 g/mol
Mass of CH3COONa required to make 250 mL of 0.575 M solution 
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How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?a)11.79 gb)15.38 gc)10.81 gd)25.35 gCorrect answer is option 'A'. Can you explain this answer?
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