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A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The molarity of the solution prepared is
  • a)
    2 M
  • b)
    1 M
  • c)
     4 M
  • d)
     5 M
Correct answer is option 'A'. Can you explain this answer?
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A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The...
Molarity

= 2 M
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A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The...
To find the molarity of the solution, we need to first calculate the number of moles of H2SO4 and then divide it by the volume of the solution in liters.

Given:
Mass of H2SO4 = 49 g
Volume of water = 250 mL = 0.25 L

1. Calculating the number of moles of H2SO4:
The molar mass of H2SO4 can be calculated as follows:
H2 (2 * 1.008 g/mol) + S (32.06 g/mol) + O4 (4 * 16.00 g/mol) = 98.09 g/mol

To calculate the number of moles of H2SO4, we divide the mass of H2SO4 by its molar mass:
Number of moles = Mass / Molar mass
Number of moles = 49 g / 98.09 g/mol
Number of moles = 0.5 mol

2. Calculating the molarity of the solution:
Molarity is defined as the number of moles of solute divided by the volume of the solution in liters.

Molarity = Number of moles / Volume of solution (in liters)
Molarity = 0.5 mol / 0.25 L
Molarity = 2 M

Therefore, the molarity of the solution prepared by dissolving 49 g of H2SO4 in 250 mL of water is 2 M.
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Community Answer
A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The...
Molarity

= 2 M
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A solution is made by dissolving 49 g of H2SO4 in 250 mL of water. The molarity of the solution prepared isa)2 Mb)1 Mc)4 Md)5 MCorrect answer is option 'A'. Can you explain this answer?
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