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What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?
- a)8.58 mL
- b)7.2 mL
- c)10 mL
- d)12 mL
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produ...
Na2SO4 + BaCI2 → BaSO4 + 2NaCl
No. of moles of BaSO4 = w/M = 10/233 = 0.0429
∴ No. of moles of Na2SO4 needed = M x V/1000
Or 0.0429 = 5 x V/1000
V = 8.58 mL
No. of moles of BaSO4 = w/M = 10/233 = 0.0429
∴ No. of moles of Na2SO4 needed = M x V/1000
Or 0.0429 = 5 x V/1000
V = 8.58 mL
Most Upvoted Answer
What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produ...
Calculation:
First, let's find out the number of moles of BaCl2 present in 25 mL of 1 M BaCl2.
Number of moles of BaCl2 = Molarity × Volume
Number of moles of BaCl2 = 1 mol/L × 25 × 10^(-3) L
Number of moles of BaCl2 = 0.025 mol
The balanced chemical equation for the reaction between Na2SO4 and BaCl2 is:
Na2SO4 + BaCl2 → 2NaCl + BaSO4
From the equation, we can see that 1 mole of BaCl2 reacts with 1 mole of Na2SO4 to produce 1 mole of BaSO4.
So, the number of moles of Na2SO4 required to produce 0.025 mol of BaSO4 is also 0.025 mol.
Molarity of Na2SO4 = 5 M
Number of moles of Na2SO4 = Molarity × Volume
0.025 mol = 5 mol/L × Volume
Volume = 0.005 L = 5 mL
Therefore, the volume of 5 M Na2SO4 required to produce 10 g of BaSO4 is:
Volume of 5 M Na2SO4 = (5 mL/0.025 mol) × (0.5 mol/1 L) = 8.58 mL
Hence, option A is the correct answer.
First, let's find out the number of moles of BaCl2 present in 25 mL of 1 M BaCl2.
Number of moles of BaCl2 = Molarity × Volume
Number of moles of BaCl2 = 1 mol/L × 25 × 10^(-3) L
Number of moles of BaCl2 = 0.025 mol
The balanced chemical equation for the reaction between Na2SO4 and BaCl2 is:
Na2SO4 + BaCl2 → 2NaCl + BaSO4
From the equation, we can see that 1 mole of BaCl2 reacts with 1 mole of Na2SO4 to produce 1 mole of BaSO4.
So, the number of moles of Na2SO4 required to produce 0.025 mol of BaSO4 is also 0.025 mol.
Molarity of Na2SO4 = 5 M
Number of moles of Na2SO4 = Molarity × Volume
0.025 mol = 5 mol/L × Volume
Volume = 0.005 L = 5 mL
Therefore, the volume of 5 M Na2SO4 required to produce 10 g of BaSO4 is:
Volume of 5 M Na2SO4 = (5 mL/0.025 mol) × (0.5 mol/1 L) = 8.58 mL
Hence, option A is the correct answer.
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Community Answer
What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produ...
To find the volume of 5 M Na2SO4 needed to produce 10 g of BaSO4, we first need to calculate the number of moles of BaSO4 that will be produced from 25 mL of 1 M BaCl2.
Given that BaCl2 will react with Na2SO4 to form BaSO4 and NaCl:
BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
From the balanced equation, we can see that 1 mole of BaCl2 will react with 1 mole of Na2SO4 to produce 1 mole of BaSO4. This means that the number of moles of BaSO4 produced will be equal to the number of moles of BaCl2 used.
Number of moles of BaSO4 produced from 25 mL of 1 M BaCl2:
= 25 mL x 1 mol/L
= 25 mmol
Now, we need to d
Given that BaCl2 will react with Na2SO4 to form BaSO4 and NaCl:
BaCl2 + Na2SO4 -> BaSO4 + 2NaCl
From the balanced equation, we can see that 1 mole of BaCl2 will react with 1 mole of Na2SO4 to produce 1 mole of BaSO4. This means that the number of moles of BaSO4 produced will be equal to the number of moles of BaCl2 used.
Number of moles of BaSO4 produced from 25 mL of 1 M BaCl2:
= 25 mL x 1 mol/L
= 25 mmol
Now, we need to d
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What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer?.
What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of 5 M Na2SO4 must be added to 25 mL of 1 M BaCl2 to produce 10 g of BaSO4?a)8.58 mLb)7.2 mLc)10 mLd)12 mLCorrect answer is option 'A'. Can you explain this answer?.
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