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12 signal each band-limited to 5 KHz are to be transmitted over a single channel by freq. division multiplexing. If AM-SSNB modulated guard band of 1 KHz is used, then the bandwidth of the multiplexed signal will be
- a)51 KHz
- b)61 KHz
- c)71 KHz
- d)81 KHz
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
12 signal each band-limited to 5 KHz are to be transmitted over a sin...
The total signal Bankwith = 5 × 12 = 60 KHz
View all questions of this test
There would be 11 guard band between 12 signal,
So, guard band width
Total band width = 60 + 11 = 71 KHz
Most Upvoted Answer
12 signal each band-limited to 5 KHz are to be transmitted over a sin...
Calculation of Bandwidth of Multiplexed Signal
Given:
Number of signals = 12
Bandwidth of each signal = 5 KHz
Guard band = 1 KHz
Formula Used:
Bandwidth of multiplexed signal = (Number of signals × Bandwidth of each signal) + Guard band
Calculation:
Number of signals = 12
Bandwidth of each signal = 5 KHz
Total bandwidth of signals = Number of signals × Bandwidth of each signal = 12 × 5 = 60 KHz
Guard band = 1 KHz
Bandwidth of multiplexed signal = Total bandwidth of signals + Guard band = 60 + 1 = 71 KHz
Therefore, the bandwidth of the multiplexed signal is 71 KHz.
Answer: (c) 71 KHz.
Given:
Number of signals = 12
Bandwidth of each signal = 5 KHz
Guard band = 1 KHz
Formula Used:
Bandwidth of multiplexed signal = (Number of signals × Bandwidth of each signal) + Guard band
Calculation:
Number of signals = 12
Bandwidth of each signal = 5 KHz
Total bandwidth of signals = Number of signals × Bandwidth of each signal = 12 × 5 = 60 KHz
Guard band = 1 KHz
Bandwidth of multiplexed signal = Total bandwidth of signals + Guard band = 60 + 1 = 71 KHz
Therefore, the bandwidth of the multiplexed signal is 71 KHz.
Answer: (c) 71 KHz.
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12 signal each band-limited to 5 KHz are to be transmitted over a single channel by freq. division multiplexing. If AM-SSNB modulated guard band of 1 KHz is used, then the bandwidth of the multiplexed signal will bea)51 KHzb)61 KHzc)71 KHzd)81 KHzCorrect answer is option 'C'. Can you explain this answer?
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