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A body moves 6 m north. 8 m east and 10 m vertically upwards, what is its resultant displacement from initial position is
- a)10√2 m
- b)10 m
- c)10/√2 m
- d)20 m
Correct answer is option 'A'. Can you explain this answer?
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A body moves 6 m north. 8 m east and 10 m vertically upwards, what is ...
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A body moves 6 m north. 8 m east and 10 m vertically upwards, what is ...
To find the resultant displacement, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the body moves 6 m north and 8 m east, so the displacement in the horizontal plane is a right triangle with sides 6 m and 8 m. Using the Pythagorean theorem, we can find the displacement in the horizontal plane:
(6^2) + (8^2) = 36 + 64 = 100
Taking the square root of both sides, we find that the displacement in the horizontal plane is 10 m.
The body also moves vertically upwards by 10 m. Since this displacement is in a different direction from the horizontal displacement, we cannot simply add them together. Instead, we need to use the Pythagorean theorem again to find the resultant displacement:
(10^2) + (10^2) = 100 + 100 = 200
Taking the square root of both sides, we find that the resultant displacement is approximately 14.14 m.
Therefore, the resultant displacement from the initial position is approximately 14.14 m.
In this case, the body moves 6 m north and 8 m east, so the displacement in the horizontal plane is a right triangle with sides 6 m and 8 m. Using the Pythagorean theorem, we can find the displacement in the horizontal plane:
(6^2) + (8^2) = 36 + 64 = 100
Taking the square root of both sides, we find that the displacement in the horizontal plane is 10 m.
The body also moves vertically upwards by 10 m. Since this displacement is in a different direction from the horizontal displacement, we cannot simply add them together. Instead, we need to use the Pythagorean theorem again to find the resultant displacement:
(10^2) + (10^2) = 100 + 100 = 200
Taking the square root of both sides, we find that the resultant displacement is approximately 14.14 m.
Therefore, the resultant displacement from the initial position is approximately 14.14 m.
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A body moves 6 m north. 8 m east and 10 m vertically upwards, what is its resultant displacement from initial position isa)10√2 mb)10 mc)10/√2 md)20 mCorrect answer is option 'A'. Can you explain this answer?
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