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A person moves 30 m north, then 30 m east, then 30√2​ m  south-west. His displacement from the original position is:
  • a)
    zero
  • b)
    28 m towards south
  • c)
    10 m towards west
  • d)
    15 m towards east
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A person moves 30 m north, then 30 m east, then 30√2m south-west...
Resolving displacement 30√2 m south-west into two rectangular components, we get
Displacement in south

∴ Effective displacement due to 30 m north and 30 m south is zero.
Also effective displacement due to 30 m east and 30 m west in zero.
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Most Upvoted Answer
A person moves 30 m north, then 30 m east, then 30√2m south-west...
M south. Describe the person's overall displacement from their starting position.

The overall displacement of the person can be found by considering their final position relative to their starting position.

Since the person moved 30 m north and then 30 m south, these two movements cancel each other out. Therefore, the person's net displacement in the north-south direction is 0 m.

Next, the person moved 30 m east. This movement is independent of the previous north-south movements. So, the person's net displacement in the east-west direction is 30 m east.

Combining the north-south and east-west displacements, the person's overall displacement from their starting position is 0 m north and 30 m east.
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A person moves 30 m north, then 30 m east, then 30√2m south-west. His displacement from the original position is:a)zerob)28 m towards southc)10 m towards westd)15 m towards eastCorrect answer is option 'A'. Can you explain this answer?
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