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A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body starts
- a)from rest and moves with uniform velocity.
- b)from rest and moves with uniform acceleration.
- c)with an initial velocity and moves with uniform acceleration.
- d)with an initial velocity and moves with uniform velocity.
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectiv...
As distance travelled in successive seconds differ by 2 m each, therefore acceleration is constant = 2ms−2
Most Upvoted Answer
A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectiv...
Given information:
- Distance covered by the body in 8th second = 20 m
- Distance covered by the body in 9th second = 22 m
- Distance covered by the body in 10th second = 24 m
We need to determine the type of motion of the body and its initial velocity and acceleration.
Solution:
Let's assume that the body starts from rest at time t=0 and moves with uniform acceleration 'a' in the x-direction.
1. Motion of the body in the 8th second:
- Distance covered by the body in the 8th second = 20 m
- Time taken by the body to cover this distance = 8 s
- Using the formula for distance covered by a body with uniform acceleration, we have:
S = ut + 0.5at^2
where S is the distance covered, u is the initial velocity, t is the time taken, and a is the acceleration.
- Since the body starts from rest, u = 0.
- Substituting the given values, we get:
20 = 0 + 0.5a(8)^2
Solving for 'a', we get:
a = 5 m/s^2
2. Motion of the body in the 9th second:
- Distance covered by the body in the 9th second = 22 m
- Time taken by the body to cover this distance = 9 s
- Using the same formula as before, we have:
S = ut + 0.5at^2
- Substituting the values, we get:
22 = 0 + 0.5a(9)^2
Solving for 'a', we get:
a = 4 m/s^2
3. Motion of the body in the 10th second:
- Distance covered by the body in the 10th second = 24 m
- Time taken by the body to cover this distance = 10 s
- Using the same formula as before, we have:
S = ut + 0.5at^2
- Substituting the values, we get:
24 = 0 + 0.5a(10)^2
Solving for 'a', we get:
a = 4.8 m/s^2
We can observe that the acceleration of the body is decreasing with time. This indicates that the body is moving with decreasing speed.
4. Initial velocity of the body:
- Using the formula for velocity of a body with uniform acceleration, we have:
v = u + at
where v is the final velocity, u is the initial velocity, t is the time taken, and a is the acceleration.
- Let's find the final velocity of the body at the end of the 10th second:
v = u + at
v = 0 + 4.8(10)
v = 48 m/s
- Now, let's find the velocity of the body at the end of the 9th second:
v = u + at
v = 0 + 4(9)
v = 36 m/s
- The change in velocity between the 9th and 10th seconds is:
Δv = v2 - v1
Δ
- Distance covered by the body in 8th second = 20 m
- Distance covered by the body in 9th second = 22 m
- Distance covered by the body in 10th second = 24 m
We need to determine the type of motion of the body and its initial velocity and acceleration.
Solution:
Let's assume that the body starts from rest at time t=0 and moves with uniform acceleration 'a' in the x-direction.
1. Motion of the body in the 8th second:
- Distance covered by the body in the 8th second = 20 m
- Time taken by the body to cover this distance = 8 s
- Using the formula for distance covered by a body with uniform acceleration, we have:
S = ut + 0.5at^2
where S is the distance covered, u is the initial velocity, t is the time taken, and a is the acceleration.
- Since the body starts from rest, u = 0.
- Substituting the given values, we get:
20 = 0 + 0.5a(8)^2
Solving for 'a', we get:
a = 5 m/s^2
2. Motion of the body in the 9th second:
- Distance covered by the body in the 9th second = 22 m
- Time taken by the body to cover this distance = 9 s
- Using the same formula as before, we have:
S = ut + 0.5at^2
- Substituting the values, we get:
22 = 0 + 0.5a(9)^2
Solving for 'a', we get:
a = 4 m/s^2
3. Motion of the body in the 10th second:
- Distance covered by the body in the 10th second = 24 m
- Time taken by the body to cover this distance = 10 s
- Using the same formula as before, we have:
S = ut + 0.5at^2
- Substituting the values, we get:
24 = 0 + 0.5a(10)^2
Solving for 'a', we get:
a = 4.8 m/s^2
We can observe that the acceleration of the body is decreasing with time. This indicates that the body is moving with decreasing speed.
4. Initial velocity of the body:
- Using the formula for velocity of a body with uniform acceleration, we have:
v = u + at
where v is the final velocity, u is the initial velocity, t is the time taken, and a is the acceleration.
- Let's find the final velocity of the body at the end of the 10th second:
v = u + at
v = 0 + 4.8(10)
v = 48 m/s
- Now, let's find the velocity of the body at the end of the 9th second:
v = u + at
v = 0 + 4(9)
v = 36 m/s
- The change in velocity between the 9th and 10th seconds is:
Δv = v2 - v1
Δ
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A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer?
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A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer?.
A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body covers 20 m, 22 m, 24 m, in 8th, 9th and 10th seconds respectively. The body startsa)from rest and moves with uniform velocity.b)from rest and moves with uniform acceleration.c)with an initial velocity and moves with uniform acceleration.d)with an initial velocity and moves with uniform velocity.Correct answer is option 'C'. Can you explain this answer?.
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