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0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 gof oxygen. What will be the percentage composition of the compound?
  • a)
    60% and 40% Band O respectively
  • b)
    40% and 60% Band O respectively
  • c)
    30% and 70% B and O respectively
  • d)
    70% and 30% B and O respectively
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
0.48 g of a sample of a compound containing boron and oxygen contains ...
Mass of compound taken = 0.48 g
Mass of boron in sample = 0.192 g
Mass of oxygen in sample = 0.288 g
Percentage of B = 0.192/0.48 x 100 = 40%
Percentage of O = 0.288/0.48 x 100 = 60%
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Most Upvoted Answer
0.48 g of a sample of a compound containing boron and oxygen contains ...
Given:
Mass of the compound = 0.48 g
Mass of boron in the compound = 0.192 g
Mass of oxygen in the compound = 0.288 g

To find: Percentage composition of the compound

Solution:
The percentage composition of a compound can be calculated by dividing the mass of each element in the compound by the total mass of the compound and multiplying by 100.

Percentage of Boron in the compound = (Mass of Boron/Mass of the Compound) x 100
= (0.192/0.48) x 100
= 40%

Percentage of Oxygen in the compound = (Mass of Oxygen/Mass of the Compound) x 100
= (0.288/0.48) x 100
= 60%

Therefore, the percentage composition of the compound is 40% Boron and 60% Oxygen, which is represented by option B.
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0.48 g of a sample of a compound containing boron and oxygen contains 0.192 g of boron and 0.288 gof oxygen. What will be the percentage composition of the compound?a)60% and 40% Band O respectivelyb)40% and 60% Band O respectivelyc)30% and 70% B and O respectivelyd)70% and 30% B and O respectivelyCorrect answer is option 'B'. Can you explain this answer?
Question Description
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