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Which of the following will have the highest f.pt. at one atmosphere?
- a)0.1 M NaCl solution
- b)0.1 M sugar solution
- c)0.1 M BaCl2 solution
- d)0.1 M FeCl3 solution
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Which of the following will have the highest f.pt. at one atmosphere?a...
For the same concentration of different solvents any colligative property ∝ = i
For NaCl, i = 2
Sugar solution, i = 1
BaCl2, i = 3; FeCl3, i = 4
Thus, for sugar solution depression in freezing point is minimum i.e., highest freezing point.
For NaCl, i = 2
Sugar solution, i = 1
BaCl2, i = 3; FeCl3, i = 4
Thus, for sugar solution depression in freezing point is minimum i.e., highest freezing point.
Most Upvoted Answer
Which of the following will have the highest f.pt. at one atmosphere?a...
Explanation:
The freezing point depression is a colligative property, which depends on the number of solute particles present in a solution. The more solute particles present, the greater the freezing point depression.
Colligative properties:
Colligative properties are properties of solutions that depend solely on the number of solute particles present, regardless of their identity. These properties include freezing point depression, boiling point elevation, vapor pressure lowering, and osmotic pressure.
Freezing point depression:
Freezing point depression is the phenomenon where the freezing point of a solvent is lowered when a non-volatile solute is added to it. The magnitude of the freezing point depression is directly proportional to the concentration of the solute particles.
Comparison of solutions:
Let's compare the given solutions to determine which one will have the highest freezing point depression:
a) 0.1 M NaCl solution:
- NaCl dissociates into Na+ and Cl- ions in water.
- Therefore, it will have 1 mole of solute particles per mole of NaCl.
- The freezing point depression will be moderate.
b) 0.1 M sugar solution:
- Sugar (such as sucrose) does not dissociate into ions in water.
- Therefore, it will have only 1 mole of solute particles per mole of sugar.
- The freezing point depression will be lower than that of the 0.1 M ionic solutions.
c) 0.1 M BaCl2 solution:
- BaCl2 dissociates into Ba2+ and 2 Cl- ions in water.
- Therefore, it will have 3 moles of solute particles per mole of BaCl2.
- The freezing point depression will be greater than that of the 0.1 M NaCl solution.
d) 0.1 M FeCl3 solution:
- FeCl3 dissociates into Fe3+ and 3 Cl- ions in water.
- Therefore, it will have 4 moles of solute particles per mole of FeCl3.
- The freezing point depression will be greater than that of the 0.1 M BaCl2 solution.
Conclusion:
Among the given options, the 0.1 M sugar solution will have the highest freezing point at one atmosphere because it has the least number of solute particles, resulting in the lowest freezing point depression.
The freezing point depression is a colligative property, which depends on the number of solute particles present in a solution. The more solute particles present, the greater the freezing point depression.
Colligative properties:
Colligative properties are properties of solutions that depend solely on the number of solute particles present, regardless of their identity. These properties include freezing point depression, boiling point elevation, vapor pressure lowering, and osmotic pressure.
Freezing point depression:
Freezing point depression is the phenomenon where the freezing point of a solvent is lowered when a non-volatile solute is added to it. The magnitude of the freezing point depression is directly proportional to the concentration of the solute particles.
Comparison of solutions:
Let's compare the given solutions to determine which one will have the highest freezing point depression:
a) 0.1 M NaCl solution:
- NaCl dissociates into Na+ and Cl- ions in water.
- Therefore, it will have 1 mole of solute particles per mole of NaCl.
- The freezing point depression will be moderate.
b) 0.1 M sugar solution:
- Sugar (such as sucrose) does not dissociate into ions in water.
- Therefore, it will have only 1 mole of solute particles per mole of sugar.
- The freezing point depression will be lower than that of the 0.1 M ionic solutions.
c) 0.1 M BaCl2 solution:
- BaCl2 dissociates into Ba2+ and 2 Cl- ions in water.
- Therefore, it will have 3 moles of solute particles per mole of BaCl2.
- The freezing point depression will be greater than that of the 0.1 M NaCl solution.
d) 0.1 M FeCl3 solution:
- FeCl3 dissociates into Fe3+ and 3 Cl- ions in water.
- Therefore, it will have 4 moles of solute particles per mole of FeCl3.
- The freezing point depression will be greater than that of the 0.1 M BaCl2 solution.
Conclusion:
Among the given options, the 0.1 M sugar solution will have the highest freezing point at one atmosphere because it has the least number of solute particles, resulting in the lowest freezing point depression.
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Which of the following will have the highest f.pt. at one atmosphere?a)0.1 M NaCl solutionb)0.1 M sugar solutionc)0.1 M BaCl2 solutiond)0.1 M FeCl3 solutionCorrect answer is option 'B'. Can you explain this answer?
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