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A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer?.

Solutions for A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A man is standing on top of a building 100 m high. He throws two balls vertically, one at t = 0 and other after a time interval (less than 2 s). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is 15 m at t = 2 s. The gap is found to remain constant. The velocities with which the balls were thrown are (Take g = 10 m s−2).a)20ms−1, 10ms−1b)10ms−1, 5ms−1c)16ms−1, 8ms−1d)30ms−1, 15ms−1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.