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A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. Its velocity with error limits is
  • a)
    (3.5 ± 0.6) m s−1
  • b)
    (3.5 ± 0.3) m s−1
  • c)
    (6.1 ± 0.6) m s−1
  • d)
    (6.1 ± 0.3) m s−1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A body travels uniformly a distance of (13.8 ± 0.2) m in a time...
Here, s = (13.8 ± 0.2) m, t = (4.0 ± 0.3)s
∴ veliocity, v = s/t = 13.8/4.0 = 3.45 m s−1
(Rounded off to first place of decimal)


= 0.0865
or Δv = v × 0.0865 = 3.45 × 0.0865
= 0.3087.
∴ velocity =(3.5 ± 0.3) m s−1.
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A body travels uniformly a distance of (13.8 ± 0.2) m in a time...
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A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. Its velocity with error limits isa)(3.5 ± 0.6) m s−1b)(3.5 ± 0.3) m s−1c)(6.1 ± 0.6) m s−1d)(6.1 ± 0.3) m s−1Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. Its velocity with error limits isa)(3.5 ± 0.6) m s−1b)(3.5 ± 0.3) m s−1c)(6.1 ± 0.6) m s−1d)(6.1 ± 0.3) m s−1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body travels uniformly a distance of (13.8 ± 0.2) m in a time (4.0 ± 0.3) s. Its velocity with error limits isa)(3.5 ± 0.6) m s−1b)(3.5 ± 0.3) m s−1c)(6.1 ± 0.6) m s−1d)(6.1 ± 0.3) m s−1Correct answer is option 'B'. Can you explain this answer?.
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