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If 1g of solute (molar mass = 50g mol−1) is dissolved in 50g of solvent and the elevation in boiling point is 1K. The molar boiling constant of the solvent is?
- a)2
- b)3
- c)2.5
- d)5
Correct answer is option 'C'. Can you explain this answer?
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If 1g of solute (molar mass = 50g mol−1) is dissolved in 50g of ...
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If 1g of solute (molar mass = 50g mol−1) is dissolved in 50g of ...
To calculate the number of moles in 1g of solute, we need to divide the mass of the solute by its molar mass.
Molar mass = 50 g/mol
Mass of solute = 1g
Number of moles = Mass of solute / Molar mass
Number of moles = 1g / 50 g/mol
Number of moles = 0.02 mol
Therefore, there are 0.02 moles of solute in 1g.
Molar mass = 50 g/mol
Mass of solute = 1g
Number of moles = Mass of solute / Molar mass
Number of moles = 1g / 50 g/mol
Number of moles = 0.02 mol
Therefore, there are 0.02 moles of solute in 1g.
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If 1g of solute (molar mass = 50g mol−1) is dissolved in 50g of solvent and the elevation in boiling point is 1K. The molar boiling constant of the solvent is?a)2b)3c)2.5d)5Correct answer is option 'C'. Can you explain this answer?
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