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Consider a silicon PN junction at T = 300K with current density 3.6 10-11 A/cm2. If the photocurrent density is 10 mA/cm2. Then find the open-circuit voltage (in V) of a solar cell when the solar intensity is increased by a factor of
Assume thermal voltage VT = 26 mV
  • a)
    0.5
  • b)
    0.6
Correct answer is between '0.5,0.6'. Can you explain this answer?
Verified Answer
Consider a silicon PN junction at T = 300K with current density 3.6 ...
Given photo current density of laser is JL = 10mA/cm2
Current density JS = 3.6 × 10−11A/cm2since the solar intensity is increased by 10 times
JL = 10 × 10mA/cm2 = 100mA/cm2The open-circuit voltage of solar cell is
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Most Upvoted Answer
Consider a silicon PN junction at T = 300K with current density 3.6 ...
Given information:
- Current density (J) = 3.6 x 10^-11 A/cm^2
- Photocurrent density (Jph) = 10 mA/cm^2 = 10^-2 A/cm^2
- Thermal voltage (VT) = 26 mV = 26 x 10^-3 V

Calculating open-circuit voltage:
The open-circuit voltage (Voc) of a solar cell is the voltage across the terminals when there is no external load connected, i.e., when the current is zero.

To calculate the open-circuit voltage, we can use the equation:

Voc = VT * ln(Jph/J)

where ln denotes the natural logarithm.

Calculating the factor by which solar intensity is increased:
Let's assume the factor by which solar intensity is increased as x.

So, the new photocurrent density (Jph_new) can be calculated as:

Jph_new = x * Jph

Calculating the open-circuit voltage for the increased solar intensity:
Substituting the values in the equation for Voc, we get:

Voc_new = VT * ln(Jph_new/J)

Voc_new = VT * ln(x * Jph/J)

Since the current density (J) remains constant, we can simplify the equation as:

Voc_new = VT * ln(x * Jph/J) = VT * ln(x)

Estimating the range of open-circuit voltage:
To estimate the range of the open-circuit voltage, we need to determine the maximum and minimum values of x.

Considering the given options, a = 0.5 and b = 0.6, let's calculate the corresponding open-circuit voltages:

Voc_a = VT * ln(a) = VT * ln(0.5)

Voc_b = VT * ln(b) = VT * ln(0.6)

Final answer:
The open-circuit voltage of the solar cell when the solar intensity is increased by a factor between 0.5 and 0.6 lies between Voc_a and Voc_b.
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Consider a silicon PN junction at T = 300K with current density 3.6 10-11 A/cm2. If the photocurrent density is 10 mA/cm2. Then find the open-circuit voltage (in V) of a solar cell when the solar intensity is increased by a factor ofAssume thermal voltage VT = 26 mVa)0.5b)0.6Correct answer is between '0.5,0.6'. Can you explain this answer?
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Consider a silicon PN junction at T = 300K with current density 3.6 10-11 A/cm2. If the photocurrent density is 10 mA/cm2. Then find the open-circuit voltage (in V) of a solar cell when the solar intensity is increased by a factor ofAssume thermal voltage VT = 26 mVa)0.5b)0.6Correct answer is between '0.5,0.6'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider a silicon PN junction at T = 300K with current density 3.6 10-11 A/cm2. If the photocurrent density is 10 mA/cm2. Then find the open-circuit voltage (in V) of a solar cell when the solar intensity is increased by a factor ofAssume thermal voltage VT = 26 mVa)0.5b)0.6Correct answer is between '0.5,0.6'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a silicon PN junction at T = 300K with current density 3.6 10-11 A/cm2. If the photocurrent density is 10 mA/cm2. Then find the open-circuit voltage (in V) of a solar cell when the solar intensity is increased by a factor ofAssume thermal voltage VT = 26 mVa)0.5b)0.6Correct answer is between '0.5,0.6'. Can you explain this answer?.
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