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A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, then
- a)capacitance will increase.
- b)energy stored will decrease.
- c)electric field will increase.
- d)voltage will decrease.
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A capacitor has some dielectric between its plates, and the capacitor ...
When the capacitor is connected to dc source, it gets charged. The battery is then disconnected, so no more charge can flow in. On removing dielectric capacitance decrease.
Energy stored (u = q2/2C) will increase.
Potential (V = q/C) will also increase.
Electric field (E = V/D) will increase.
Energy stored (u = q2/2C) will increase.
Potential (V = q/C) will also increase.
Electric field (E = V/D) will increase.
Most Upvoted Answer
A capacitor has some dielectric between its plates, and the capacitor ...
Explanation:
When a capacitor is connected to a DC source, it charges up and stores electric energy in the form of electric field between its plates. The dielectric material between the plates increases the capacitance of the capacitor by reducing the effective separation between the plates and increasing the electric field strength.
When the battery is disconnected and the dielectric is removed, several changes occur:
1. Capacitance will increase:
The capacitance of a capacitor is given by the formula C = εA/d, where ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates. When the dielectric is removed, the distance between the plates increases, resulting in an increase in capacitance.
2. Energy stored will decrease:
The energy stored in a capacitor is given by the formula E = 1/2 CV^2, where C is the capacitance and V is the voltage across the capacitor. When the dielectric is removed, the capacitance increases, but the voltage across the capacitor remains the same. Therefore, the energy stored in the capacitor decreases because the energy is directly proportional to the capacitance.
3. Electric field will increase:
The electric field between the plates of a capacitor is given by the formula E = V/d, where V is the voltage across the capacitor and d is the distance between the plates. When the dielectric is removed, the distance between the plates increases, but the voltage across the capacitor remains the same. Therefore, the electric field between the plates increases because the electric field is inversely proportional to the distance.
4. Voltage will decrease:
When the dielectric is removed, the capacitance of the capacitor increases, but the charge on the capacitor remains the same. According to the formula Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage across the capacitor, the voltage across the capacitor decreases because the voltage is inversely proportional to the capacitance.
Therefore, the correct answer is option 'C' - the electric field will increase.
When a capacitor is connected to a DC source, it charges up and stores electric energy in the form of electric field between its plates. The dielectric material between the plates increases the capacitance of the capacitor by reducing the effective separation between the plates and increasing the electric field strength.
When the battery is disconnected and the dielectric is removed, several changes occur:
1. Capacitance will increase:
The capacitance of a capacitor is given by the formula C = εA/d, where ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates. When the dielectric is removed, the distance between the plates increases, resulting in an increase in capacitance.
2. Energy stored will decrease:
The energy stored in a capacitor is given by the formula E = 1/2 CV^2, where C is the capacitance and V is the voltage across the capacitor. When the dielectric is removed, the capacitance increases, but the voltage across the capacitor remains the same. Therefore, the energy stored in the capacitor decreases because the energy is directly proportional to the capacitance.
3. Electric field will increase:
The electric field between the plates of a capacitor is given by the formula E = V/d, where V is the voltage across the capacitor and d is the distance between the plates. When the dielectric is removed, the distance between the plates increases, but the voltage across the capacitor remains the same. Therefore, the electric field between the plates increases because the electric field is inversely proportional to the distance.
4. Voltage will decrease:
When the dielectric is removed, the capacitance of the capacitor increases, but the charge on the capacitor remains the same. According to the formula Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V is the voltage across the capacitor, the voltage across the capacitor decreases because the voltage is inversely proportional to the capacitance.
Therefore, the correct answer is option 'C' - the electric field will increase.
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A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer?
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A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer?.
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A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A capacitor has some dielectric between its plates, and the capacitor is connected to a dc source. The battery is now disconnected and then the dielectric is removed, thena)capacitance will increase.b)energy stored will decrease.c)electric field will increase.d)voltage will decrease.Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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