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A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates

  • a)
    increases

  • b)
    decreases

  • c)
    does not change

  • d)
    becomes zero

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A parallel plate air capacitor is charged to a potential difference of...


Correct answer is A.
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A parallel plate air capacitor is charged to a potential difference of...
Explanation:

When a capacitor is charged, it stores electrical energy in the form of electric field between its plates. The potential difference between the plates is directly proportional to the amount of charge stored in the capacitor, and inversely proportional to the distance between the plates.

When the distance between the plates is increased, the capacitance of the capacitor decreases. This means that the same amount of charge stored in the capacitor is now distributed over a larger area, resulting in a decrease in the potential difference between the plates.

However, since the capacitor is initially charged to a potential difference of V volts, it still contains that amount of charge even after the distance between the plates is increased. This means that the same amount of charge is now distributed over a larger area, resulting in a lower electric field strength between the plates.

Since the electric field strength is directly proportional to the potential difference between the plates, and the distance between the plates has increased, the potential difference between the plates increases to maintain the same electric field strength.

Therefore, the correct answer is option 'A': the potential difference between the plates increases.
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A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the platesa)increasesb)decreasesc)does not changed)becomes zeroCorrect answer is option 'A'. Can you explain this answer?
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