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A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.
- a)25.66
- b)35.66
- c)45.66
- d)55.66
Correct answer is option 'A'. Can you explain this answer?
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A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter...
= 25.66%
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A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter...
Given:
- Length of copper tin, L = 600 mm
- Diameter of copper tin, D = 5 mm
- Thermal conductivity of copper tin, k = 380 W/m-K
- Temperature of air stream, T∞ = 200°C
- Convective heat transfer coefficient, h = 20 W/m²-K
- Temperature of copper tin base, Tbase = 150°C
We need to find the efficiency of the copper tin.
Formula used:
- Rate of heat transfer through conduction, Qcond = k * A * (Tbase - T∞) / L
- Rate of heat transfer through convection, Qconv = h * A * (Tbase - T∞)
- Efficiency, η = Qconv / (Qconv + Qcond)
Calculation:
- Cross-sectional area of copper tin, A = π/4 * D² = π/4 * (5*10^-3)² = 1.96*10^-5 m²
- Rate of heat transfer through conduction, Qcond = k * A * (Tbase - T∞) / L
= 380 * 1.96*10^-5 * (150-200) / 0.6
= -0.3933 W
- Rate of heat transfer through convection, Qconv = h * A * (Tbase - T∞)
= 20 * 1.96*10^-5 * (150-200)
= -0.3933 W
- Efficiency, η = Qconv / (Qconv + Qcond)
= -0.3933 / (-0.3933 + (-0.3933))
= 0.2566 or 25.66%
Therefore, the efficiency of the copper tin is 25.66%.
Note: The negative sign in the heat transfer rates indicates that heat is flowing out of the copper tin.
- Length of copper tin, L = 600 mm
- Diameter of copper tin, D = 5 mm
- Thermal conductivity of copper tin, k = 380 W/m-K
- Temperature of air stream, T∞ = 200°C
- Convective heat transfer coefficient, h = 20 W/m²-K
- Temperature of copper tin base, Tbase = 150°C
We need to find the efficiency of the copper tin.
Formula used:
- Rate of heat transfer through conduction, Qcond = k * A * (Tbase - T∞) / L
- Rate of heat transfer through convection, Qconv = h * A * (Tbase - T∞)
- Efficiency, η = Qconv / (Qconv + Qcond)
Calculation:
- Cross-sectional area of copper tin, A = π/4 * D² = π/4 * (5*10^-3)² = 1.96*10^-5 m²
- Rate of heat transfer through conduction, Qcond = k * A * (Tbase - T∞) / L
= 380 * 1.96*10^-5 * (150-200) / 0.6
= -0.3933 W
- Rate of heat transfer through convection, Qconv = h * A * (Tbase - T∞)
= 20 * 1.96*10^-5 * (150-200)
= -0.3933 W
- Efficiency, η = Qconv / (Qconv + Qcond)
= -0.3933 / (-0.3933 + (-0.3933))
= 0.2566 or 25.66%
Therefore, the efficiency of the copper tin is 25.66%.
Note: The negative sign in the heat transfer rates indicates that heat is flowing out of the copper tin.
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A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer?
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A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer?.
A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A longitudinal copper tin (k=380 W/m-K) 600 mm long and 5 mm diameter is expose of air stream at 200C. The convective heat transfer coefficient is 20 W/m2-K. If the tin base temperature is 1500C, then efficiency of the tin __________%.a)25.66b)35.66c)45.66d)55.66Correct answer is option 'A'. Can you explain this answer?.
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