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Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg?
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Suppose the charge of a proton an electron differ slightly. One of the...
Introduction:
In this scenario, we are given that the charges of a proton and an electron differ slightly. Let the charge of the proton be e and the charge of the electron be (e + Δe-). We are also given that the net electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is zero. We need to determine the order of Δe.
Gravitational force between hydrogen atoms:
The gravitational force between two hydrogen atoms can be calculated using Newton's law of gravitation:
F_grav = G * (m1 * m2) / r^2
where F_grav is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the hydrogen atoms, and r is the distance between them.
Electrostatic force between hydrogen atoms:
The electrostatic force between two charged particles can be calculated using Coulomb's law:
F_elec = k * (q1 * q2) / r^2
where F_elec is the electrostatic force, k is the electrostatic constant, q1 and q2 are the charges of the particles, and r is the distance between them.
Net force between hydrogen atoms:
Since the net electrostatic force and gravitational force between the hydrogen atoms is zero, we can equate the two forces:
F_grav = F_elec
Substituting the values:
We can substitute the expressions for gravitational and electrostatic forces into the equation:
G * (m1 * m2) / r^2 = k * (q1 * q2) / r^2
Mass of hydrogen atom:
The mass of a hydrogen atom is given as 1.67×10^-27 kg.
Charge of proton and electron:
The charge of a proton is e, and the charge of an electron is (e + Δe-).
Simplifying the equation:
By canceling out the common terms and rearranging the equation, we can solve for Δe:
(m1 * m2) = (q1 * q2) * (k / G)
(mass of hydrogen atom)^2 = (charge of proton) * (charge of electron) * (k / G)
(1.67×10^-27 kg)^2 = e * (e + Δe-) * (k / G)
Calculating Δe:
We can solve the equation for Δe by substituting the known values:
(1.67×10^-27 kg)^2 = e * (e + Δe-) * (k / G)
By solving this equation, we can determine the order of Δe.
In this scenario, we are given that the charges of a proton and an electron differ slightly. Let the charge of the proton be e and the charge of the electron be (e + Δe-). We are also given that the net electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is zero. We need to determine the order of Δe.
Gravitational force between hydrogen atoms:
The gravitational force between two hydrogen atoms can be calculated using Newton's law of gravitation:
F_grav = G * (m1 * m2) / r^2
where F_grav is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the hydrogen atoms, and r is the distance between them.
Electrostatic force between hydrogen atoms:
The electrostatic force between two charged particles can be calculated using Coulomb's law:
F_elec = k * (q1 * q2) / r^2
where F_elec is the electrostatic force, k is the electrostatic constant, q1 and q2 are the charges of the particles, and r is the distance between them.
Net force between hydrogen atoms:
Since the net electrostatic force and gravitational force between the hydrogen atoms is zero, we can equate the two forces:
F_grav = F_elec
Substituting the values:
We can substitute the expressions for gravitational and electrostatic forces into the equation:
G * (m1 * m2) / r^2 = k * (q1 * q2) / r^2
Mass of hydrogen atom:
The mass of a hydrogen atom is given as 1.67×10^-27 kg.
Charge of proton and electron:
The charge of a proton is e, and the charge of an electron is (e + Δe-).
Simplifying the equation:
By canceling out the common terms and rearranging the equation, we can solve for Δe:
(m1 * m2) = (q1 * q2) * (k / G)
(mass of hydrogen atom)^2 = (charge of proton) * (charge of electron) * (k / G)
(1.67×10^-27 kg)^2 = e * (e + Δe-) * (k / G)
Calculating Δe:
We can solve the equation for Δe by substituting the known values:
(1.67×10^-27 kg)^2 = e * (e + Δe-) * (k / G)
By solving this equation, we can determine the order of Δe.
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Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg?
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Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg?.
Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose the charge of a proton an electron differ slightly. One of them is e- the other is (e delta e-) if the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance a apart is 0 then delta e of the order of (given mass of H=1.67×10Kg?.
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