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What will be the weight of CO having the same number of oxygen atoms as present in 22 g of CO2?
- a)28 g
- b)22 g
- c)44 g
- d)72 g
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
What will be the weight of CO having the same number of oxygen atoms a...
No. of O atoms in CO2 = 2
Molar mass of CO2 = 44 g
44 g = 1 mol ⇒ 22 g = 0.5 mol
1 mole of CO2 contains = 2 x 6.023 x 1023 O atoms
0.5 mole of CO2 = 6.023 x 1023 O atoms
1 mole of CO = 6.023 x 1023 O atoms
Mass of 1 mole of CO = 12 + 16 = 28 g
Molar mass of CO2 = 44 g
44 g = 1 mol ⇒ 22 g = 0.5 mol
1 mole of CO2 contains = 2 x 6.023 x 1023 O atoms
0.5 mole of CO2 = 6.023 x 1023 O atoms
1 mole of CO = 6.023 x 1023 O atoms
Mass of 1 mole of CO = 12 + 16 = 28 g
Most Upvoted Answer
What will be the weight of CO having the same number of oxygen atoms a...
Given:
Mass of CO2 = 22 g
We need to find the weight of CO having the same number of oxygen atoms as present in 22 g of CO2.
Step-by-step solution:
1. Find the number of oxygen atoms in 22 g of CO2.
We know that the molar mass of CO2 is 44 g/mol (12 g/mol + 2 x 16 g/mol).
So, the number of moles of CO2 in 22 g can be calculated as:
n(CO2) = mass/molar mass = 22 g/44 g/mol = 0.5 mol
In one mole of CO2, there are 2 oxygen atoms.
So, in 0.5 mol of CO2, the number of oxygen atoms can be calculated as:
Number of oxygen atoms = 0.5 mol x 2 = 1 mol
Therefore, there is 1 mole of oxygen atoms in 22 g of CO2.
2. Find the weight of CO with the same number of oxygen atoms.
Now, we need to find the weight of CO with 1 mole of oxygen atoms.
In one mole of CO, there is 1 oxygen atom.
So, to get 1 mole of oxygen atoms, we need 1 mole of CO.
Therefore, the weight of CO with the same number of oxygen atoms as present in 22 g of CO2 will be equal to the molar mass of CO, which is 28 g/mol (12 g/mol + 16 g/mol).
Hence, the correct option is (a) 28 g.
Mass of CO2 = 22 g
We need to find the weight of CO having the same number of oxygen atoms as present in 22 g of CO2.
Step-by-step solution:
1. Find the number of oxygen atoms in 22 g of CO2.
We know that the molar mass of CO2 is 44 g/mol (12 g/mol + 2 x 16 g/mol).
So, the number of moles of CO2 in 22 g can be calculated as:
n(CO2) = mass/molar mass = 22 g/44 g/mol = 0.5 mol
In one mole of CO2, there are 2 oxygen atoms.
So, in 0.5 mol of CO2, the number of oxygen atoms can be calculated as:
Number of oxygen atoms = 0.5 mol x 2 = 1 mol
Therefore, there is 1 mole of oxygen atoms in 22 g of CO2.
2. Find the weight of CO with the same number of oxygen atoms.
Now, we need to find the weight of CO with 1 mole of oxygen atoms.
In one mole of CO, there is 1 oxygen atom.
So, to get 1 mole of oxygen atoms, we need 1 mole of CO.
Therefore, the weight of CO with the same number of oxygen atoms as present in 22 g of CO2 will be equal to the molar mass of CO, which is 28 g/mol (12 g/mol + 16 g/mol).
Hence, the correct option is (a) 28 g.
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What will be the weight of CO having the same number of oxygen atoms as present in 22 g of CO2?a)28 gb)22 gc)44 gd)72 gCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What will be the weight of CO having the same number of oxygen atoms as present in 22 g of CO2?a)28 gb)22 gc)44 gd)72 gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What will be the weight of CO having the same number of oxygen atoms as present in 22 g of CO2?a)28 gb)22 gc)44 gd)72 gCorrect answer is option 'A'. Can you explain this answer?.
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