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A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?
- a)44.8 L
- b)22.4 L
- c)11.2 L
- d)67.2 L
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much ...
2 g of H2 = 1 mole, 32 g of O2 = 1 mole
Total volume of 2 moles of gases at NTP = 2 x 22.4 L
= 44.8L
Total volume of 2 moles of gases at NTP = 2 x 22.4 L
= 44.8L
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A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much ...
Given:
Mass of hydrogen = 2 g
Mass of oxygen = 32 g
To find: Volume of the mixture at NTP
Solution:
1. Calculation of moles of hydrogen and oxygen:
Moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen
Molar mass of hydrogen = 2 g/mol
Moles of hydrogen = 2 g / 2 g/mol = 1 mol
Moles of oxygen = Mass of oxygen / Molar mass of oxygen
Molar mass of oxygen = 32 g/mol
Moles of oxygen = 32 g / 32 g/mol = 1 mol
2. Calculation of total moles of gas:
Total moles of gas = Moles of hydrogen + Moles of oxygen
Total moles of gas = 1 mol + 1 mol = 2 mol
3. Calculation of volume of gas at NTP:
1 mol of gas at NTP = 22.4 L
2 mol of gas at NTP = 44.8 L
Therefore, the volume of the mixture at NTP is 44.8 L.
Answer: Option A (44.8 L)
Mass of hydrogen = 2 g
Mass of oxygen = 32 g
To find: Volume of the mixture at NTP
Solution:
1. Calculation of moles of hydrogen and oxygen:
Moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen
Molar mass of hydrogen = 2 g/mol
Moles of hydrogen = 2 g / 2 g/mol = 1 mol
Moles of oxygen = Mass of oxygen / Molar mass of oxygen
Molar mass of oxygen = 32 g/mol
Moles of oxygen = 32 g / 32 g/mol = 1 mol
2. Calculation of total moles of gas:
Total moles of gas = Moles of hydrogen + Moles of oxygen
Total moles of gas = 1 mol + 1 mol = 2 mol
3. Calculation of volume of gas at NTP:
1 mol of gas at NTP = 22.4 L
2 mol of gas at NTP = 44.8 L
Therefore, the volume of the mixture at NTP is 44.8 L.
Answer: Option A (44.8 L)
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A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer?.
A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mixture having 2 g of hydrogen and 32 g of oxygen occupies how much volume at NTP?a)44.8 Lb)22.4 Lc)11.2 Ld)67.2 LCorrect answer is option 'A'. Can you explain this answer?.
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