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A giant telescope in an observatory has an objective of focal length 19 m and an eye-piece of focal length 1.0 cm. In normal adjustment, the telescope is used to view the moon. What is the diameter of the image of the moon formed by the objective ? The diameter of the moon is 3.5 × 106 m and the radius of the lunar orbit round the earth is 3.8 × 108 m.
  • a)
    10 cm
  • b)
    12.5 cm
  • c)
    15 cm
  • d)
    17.5 cm
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A giant telescope in an observatory has an objective of focal length 1...
As u ≫ f0 , v = f0 = 19 m.
Now u = -3.8 × 108 m. Therefore, magnification produced by the objective is

∴ Diameter of the image of moon is 3.5 × 106 × 0.5 × 10-7 = 0.175 m = 17.5 cm
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Most Upvoted Answer
A giant telescope in an observatory has an objective of focal length 1...
To find the diameter of the image formed by the objective, we can use the formula for magnification:

magnification = focal length of objective / focal length of eyepiece

In this case, the focal length of the objective is given as 19 m, and the focal length of the eyepiece is given as 1.0 cm, which is equivalent to 0.01 m.

magnification = 19 m / 0.01 m = 1900

The magnification tells us how much larger the image is compared to the actual object. In this case, the image formed by the objective is 1900 times larger than the moon.

Therefore, the diameter of the image of the moon formed by the objective is:

diameter of image = diameter of the moon x magnification
= 3.5 km x 1900
= 6650 km
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A giant telescope in an observatory has an objective of focal length 19 m and an eye-piece of focal length 1.0 cm. In normal adjustment, the telescope is used to view the moon. What is the diameter of the image of the moon formed by the objective ? The diameter of the moon is 3.5 × 106 m and the radius of the lunar orbit round the earth is 3.8 × 108 m.a)10 cmb)12.5 cmc)15 cmd)17.5 cmCorrect answer is option 'D'. Can you explain this answer?
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