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A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm is
  • a)
    100
  • b)
    50
  • c)
    25
  • d)
    5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A reflecting telescope has a large mirror for its objective with radiu...
The focal length of objective mirror
f0 = R/2 = 80/2 = 40 cm
and focal length of eye piece = 1.6 cm
∴ magnifying power, m = f0/fe = 40/1.6 = 25
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Most Upvoted Answer
A reflecting telescope has a large mirror for its objective with radiu...
Objective:
To find the magnifying power of a reflecting telescope.

Given:
- Radius of curvature of the objective mirror (R) = 80 cm
- Focal length of the eyepiece (f) = 1.6 cm

Formula:
The magnifying power (M) of a telescope is given by the formula:
M = -fo/fe

where fo is the focal length of the objective and fe is the focal length of the eyepiece.

Calculation:
Given that R = 80 cm, we can use the mirror formula to find the focal length of the objective:
1/f = 1/R
1/f = 1/80
f = 80 cm

Substituting the values of fo and fe into the magnifying power formula:
M = -fo/fe
M = -80/1.6
M = -50

Since magnifying power is a positive quantity, we take the absolute value of the result:
|M| = 50

Therefore, the magnifying power of the reflecting telescope is 50.

Answer:
The correct answer is option (b) 50.
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A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm isa)100b)50c)25d)5Correct answer is option 'C'. Can you explain this answer?
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