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A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm is
- a)100
- b)50
- c)25
- d)5
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A reflecting telescope has a large mirror for its objective with radiu...
The focal length of objective mirror
f0 = R/2 = 80/2 = 40 cm
and focal length of eye piece = 1.6 cm
∴ magnifying power, m = f0/fe = 40/1.6 = 25
f0 = R/2 = 80/2 = 40 cm
and focal length of eye piece = 1.6 cm
∴ magnifying power, m = f0/fe = 40/1.6 = 25
Most Upvoted Answer
A reflecting telescope has a large mirror for its objective with radiu...
Objective:
To find the magnifying power of a reflecting telescope.
Given:
- Radius of curvature of the objective mirror (R) = 80 cm
- Focal length of the eyepiece (f) = 1.6 cm
Formula:
The magnifying power (M) of a telescope is given by the formula:
M = -fo/fe
where fo is the focal length of the objective and fe is the focal length of the eyepiece.
Calculation:
Given that R = 80 cm, we can use the mirror formula to find the focal length of the objective:
1/f = 1/R
1/f = 1/80
f = 80 cm
Substituting the values of fo and fe into the magnifying power formula:
M = -fo/fe
M = -80/1.6
M = -50
Since magnifying power is a positive quantity, we take the absolute value of the result:
|M| = 50
Therefore, the magnifying power of the reflecting telescope is 50.
Answer:
The correct answer is option (b) 50.
To find the magnifying power of a reflecting telescope.
Given:
- Radius of curvature of the objective mirror (R) = 80 cm
- Focal length of the eyepiece (f) = 1.6 cm
Formula:
The magnifying power (M) of a telescope is given by the formula:
M = -fo/fe
where fo is the focal length of the objective and fe is the focal length of the eyepiece.
Calculation:
Given that R = 80 cm, we can use the mirror formula to find the focal length of the objective:
1/f = 1/R
1/f = 1/80
f = 80 cm
Substituting the values of fo and fe into the magnifying power formula:
M = -fo/fe
M = -80/1.6
M = -50
Since magnifying power is a positive quantity, we take the absolute value of the result:
|M| = 50
Therefore, the magnifying power of the reflecting telescope is 50.
Answer:
The correct answer is option (b) 50.
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A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm isa)100b)50c)25d)5Correct answer is option 'C'. Can you explain this answer?
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A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm isa)100b)50c)25d)5Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm isa)100b)50c)25d)5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A reflecting telescope has a large mirror for its objective with radius of curvature equal to 80 cm. The magnifying power of this telescope if eye piece used has a focal length of 1.6 cm isa)100b)50c)25d)5Correct answer is option 'C'. Can you explain this answer?.
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