Two particles of equal charges after being accelerated through the sam...

And Bqv = Mv
2/R Or

Using (i)
or

∴ M ∝ R
2 (∵ B, q and V are same for the given two particles)
Hence (M
1/M
2) = (R
1/R
2)
2 View all questions of this testTwo particles of equal charges after being accelerated through the sam...
Explanation:
Given:
- Two particles of equal charges
- Accelerated through the same potential difference
- Enter in a uniform transverse magnetic field
- Describe circular paths of radii R1 and R2
To find:
- The ratio of their respective masses (M1/M2)
Formula:
The centripetal force for a charged particle moving in a magnetic field is given by the formula:
F = qvB
The centripetal force is also given by the formula:
F = mv²/R
Where:
- F is the centripetal force
- q is the charge of the particle
- v is the velocity of the particle
- B is the magnetic field
- m is the mass of the particle
- R is the radius of the circular path
Derivation:
- Since the particles have the same charge and are accelerated through the same potential difference, the magnitude of their velocities (v1 and v2) will be the same.
- Therefore, the centripetal forces for both particles will be the same.
- Equating the two formulas for centripetal force:
qv1B = mv1²/R1
qv2B = mv2²/R2
- Dividing the second equation by the first equation:
(v2/v1) = (m2/m1) * (R1/R2)
- Since (v2/v1) = 1 (as the velocities are the same), the equation simplifies to:
1 = (m2/m1) * (R1/R2)
- Rearranging the equation:
(m2/m1) = (R1/R2)²
Therefore, the ratio of their respective masses is equal to the square of the ratio of their radii. Hence, the correct answer is option 'B' (R1/R2)^2.