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The horizontal component of earth's magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction is
- a)3.0 x 10-5 N m-1
- b)3.2 x 10-5 N m-1
- c)3.6 x 10-5 N m-1
- d)3.8 x 10-5 N m-1
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The horizontal component of earths magnetic field at a certain place i...
Force per unit length f = F/l = IB sinθ
when the current is flowing from east to west then θ = 90°, hence
f = IBsin 90° = 1.2 x 3 x 10-5 x 1 = 3.6 x 10-5 N m-1.
when the current is flowing from east to west then θ = 90°, hence
f = IBsin 90° = 1.2 x 3 x 10-5 x 1 = 3.6 x 10-5 N m-1.
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Community Answer
The horizontal component of earths magnetic field at a certain place i...
**Given:**
- Horizontal component of Earth's magnetic field (B) = 3.0 x 10^-5 T (from south to north)
- Current (I) = 1.2 A (east to west direction)
**To find:**
Force per unit length on the conductor
**Formula:**
The force per unit length on a straight conductor carrying current in a magnetic field is given by the formula:
F = BIL
Where:
F = Force per unit length (N m^-1)
B = Magnetic field strength (T)
I = Current (A)
L = Length of the conductor (m)
**Explanation:**
To find the force per unit length on the conductor, we can substitute the given values into the formula:
F = BIL
Given:
B = 3.0 x 10^-5 T
I = 1.2 A
Now, we need to determine the length of the conductor. However, the length is not provided in the question. Therefore, we cannot calculate the exact force per unit length without the length of the conductor.
Hence, the given options are incorrect as they provide a specific value for the force per unit length, which cannot be determined without the length of the conductor.
Therefore, none of the options provided in the question are correct.
- Horizontal component of Earth's magnetic field (B) = 3.0 x 10^-5 T (from south to north)
- Current (I) = 1.2 A (east to west direction)
**To find:**
Force per unit length on the conductor
**Formula:**
The force per unit length on a straight conductor carrying current in a magnetic field is given by the formula:
F = BIL
Where:
F = Force per unit length (N m^-1)
B = Magnetic field strength (T)
I = Current (A)
L = Length of the conductor (m)
**Explanation:**
To find the force per unit length on the conductor, we can substitute the given values into the formula:
F = BIL
Given:
B = 3.0 x 10^-5 T
I = 1.2 A
Now, we need to determine the length of the conductor. However, the length is not provided in the question. Therefore, we cannot calculate the exact force per unit length without the length of the conductor.
Hence, the given options are incorrect as they provide a specific value for the force per unit length, which cannot be determined without the length of the conductor.
Therefore, none of the options provided in the question are correct.
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The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer?.
The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer?.
Solutions for The horizontal component of earths magnetic field at a certain place is 3.0 x 10-5 T and having a direction from the geographic south to geographic north. The force per unit length on a very long straight conductor carrying a steady current of 1.2 A in east to west direction isa)3.0 x 10-5 N m-1b)3.2 x 10-5 N m-1c)3.6 x 10-5 N m-1d)3.8 x 10-5 N m-1Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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