A ray of light strikes a transparent rectangular slab of refractive in...
From figure,
i + θ + 30∘ = 180∘ (∵ i = r = 45∘)
45∘ + θ + 30∘ = 180∘ or
θ = 180∘ − 75∘ = 105∘
Hence, the angle between reflected and refracted rays is 105∘
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A ray of light strikes a transparent rectangular slab of refractive in...
Let's call the refractive index of the rectangular slab "n". When a ray of light strikes the slab, it will bend at the interface between the air and the slab due to the change in refractive index.
The angle of incidence (i) and the angle of refraction (r) can be related through Snell's law:
n1 * sin(i) = n2 * sin(r)
where n1 is the refractive index of the air (which is approximately 1) and n2 is the refractive index of the slab (which is given as "n" in the problem).
In this case, the ray of light is entering the slab from the air, so n1 = 1 and n2 = n. Let's assume that the incident ray is perpendicular to one of the faces of the rectangular slab (so i = 0). This means that the ray will not bend at the first interface.
However, when the ray reaches the second interface (between the slab and the air again), it will bend again due to the change in refractive index. The angle of refraction can be found using Snell's law again, this time with n1 = n and n2 = 1:
n * sin(r) = 1 * sin(theta)
where theta is the angle between the refracted ray and the normal to the surface.
Since the slab is rectangular, we can assume that the angle theta will be the same for both sides of the slab (i.e. the ray will be symmetric). Therefore, we can find theta by using the fact that the sum of the angles in a rectangle is 360 degrees:
theta + r + r + i = 360
Since i = 0, we can simplify this to:
theta + 2r = 360
Now we can solve for theta using the value we found for r from Snell's law:
n * sin(r) = sin(theta)
sin(theta) = n * sin(r) = n * sin(arcsin(1/n)) = sqrt(n^2 - 1)
(Note that we used the fact that sin(arcsin(x)) = x.)
Now we can use this value of theta to solve for the angle of refraction on the second interface:
theta + 2r = 360
r = (360 - theta)/2 = (360 - arcsin(sqrt(n^2 - 1)))/2
So we have found the angle of refraction on the second interface, and we can use this to determine the path of the refracted ray. We can also find the deviation angle of the ray by subtracting the incident angle from the final angle:
deviation angle = r - i = (360 - arcsin(sqrt(n^2 - 1)))/2
This expression gives us the amount that the ray is deflected as it passes through the rectangular slab.
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