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A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?
- a)1.00 cm
- b)2.37 cm
- c)0.51 cm
- d)3.93 cm
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A tank is filled with water to a height of 15.5 cm. The apparent depth...
Actual depth of the needle in water
h1 = 15.5cm
Apparent depth of needle in water h2 = 8.5cm
For another liquid with μ' = 1.94
Apparent depth, H = 15.5/1.94 = 7.99cm
Here, H is less than h2. Thus to focus the needle again, the microscope should be moved up by the distance 8.5 − 7.99 = 0.51cm
h1 = 15.5cm
Apparent depth of needle in water h2 = 8.5cm
For another liquid with μ' = 1.94
Apparent depth, H = 15.5/1.94 = 7.99cm
Here, H is less than h2. Thus to focus the needle again, the microscope should be moved up by the distance 8.5 − 7.99 = 0.51cm
Most Upvoted Answer
A tank is filled with water to a height of 15.5 cm. The apparent depth...
Given:
- Height of water in the tank = 15.5 cm
- Apparent depth of the needle in water = 8.5 cm
- Refractive index of the liquid = 1.94
To find:
The distance by which the microscope has to be moved to focus on the needle again.
Concept:
The apparent depth of an object immersed in a liquid is given by the formula:
Apparent depth = Actual depth / Refractive index of the liquid
Calculation:
1. In the first case, when the tank is filled with water:
- Actual depth of the needle = 15.5 cm
- Apparent depth of the needle = 8.5 cm
2. Using the formula, we can write:
8.5 cm = 15.5 cm / Refractive index of water
Refractive index of water = 15.5 cm / 8.5 cm
Refractive index of water = 1.82
3. In the second case, when the water is replaced by a liquid with refractive index 1.94:
- Actual depth of the needle = 15.5 cm
- Refractive index of the liquid = 1.94
4. Using the formula, we can write:
Apparent depth of the needle = Actual depth of the needle / Refractive index of the liquid
Apparent depth of the needle = 15.5 cm / 1.94
Apparent depth of the needle = 8 cm (approximately)
5. The microscope needs to be moved by the difference in apparent depths in the two cases:
Distance to be moved = Apparent depth in the second case - Apparent depth in the first case
Distance to be moved = 8 cm - 8.5 cm
Distance to be moved = -0.5 cm (approximately)
6. The negative sign indicates that the microscope needs to be moved in the opposite direction. Taking the absolute value, the distance to be moved is 0.5 cm.
Therefore, the microscope needs to be moved by 0.5 cm to focus on the needle again.
Answer:
The correct answer is option (c) 0.51 cm.
- Height of water in the tank = 15.5 cm
- Apparent depth of the needle in water = 8.5 cm
- Refractive index of the liquid = 1.94
To find:
The distance by which the microscope has to be moved to focus on the needle again.
Concept:
The apparent depth of an object immersed in a liquid is given by the formula:
Apparent depth = Actual depth / Refractive index of the liquid
Calculation:
1. In the first case, when the tank is filled with water:
- Actual depth of the needle = 15.5 cm
- Apparent depth of the needle = 8.5 cm
2. Using the formula, we can write:
8.5 cm = 15.5 cm / Refractive index of water
Refractive index of water = 15.5 cm / 8.5 cm
Refractive index of water = 1.82
3. In the second case, when the water is replaced by a liquid with refractive index 1.94:
- Actual depth of the needle = 15.5 cm
- Refractive index of the liquid = 1.94
4. Using the formula, we can write:
Apparent depth of the needle = Actual depth of the needle / Refractive index of the liquid
Apparent depth of the needle = 15.5 cm / 1.94
Apparent depth of the needle = 8 cm (approximately)
5. The microscope needs to be moved by the difference in apparent depths in the two cases:
Distance to be moved = Apparent depth in the second case - Apparent depth in the first case
Distance to be moved = 8 cm - 8.5 cm
Distance to be moved = -0.5 cm (approximately)
6. The negative sign indicates that the microscope needs to be moved in the opposite direction. Taking the absolute value, the distance to be moved is 0.5 cm.
Therefore, the microscope needs to be moved by 0.5 cm to focus on the needle again.
Answer:
The correct answer is option (c) 0.51 cm.
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A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer?
Question Description
A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer?.
A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer?.
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A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A tank is filled with water to a height of 15.5 cm. The apparent depth of a needle lying at the bottom of the tank is measured by a microscope to be 8.5 cm. If water is replaced by a liquid of refractive index 1.94 upto the same height, by what distance would the microscope have to be moved to focus on the needle again ?a)1.00 cmb)2.37 cmc)0.51 cmd)3.93 cmCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
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