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A graph is plotted between log (x/m) and P according to the equation x/m = kp1/nWhich of the following statements about this graph is not correct?a)The figure shows Freundlich adsorption isothermb)The figure shows Langmuir adsorption isothermc)The adsorption varies directly with pressured)The factor 1/n can have values between 0 and 1Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A graph is plotted between log (x/m) and P according to the equation x/m = kp1/nWhich of the following statements about this graph is not correct?a)The figure shows Freundlich adsorption isothermb)The figure shows Langmuir adsorption isothermc)The adsorption varies directly with pressured)The factor 1/n can have values between 0 and 1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A graph is plotted between log (x/m) and P according to the equation x/m = kp1/nWhich of the following statements about this graph is not correct?a)The figure shows Freundlich adsorption isothermb)The figure shows Langmuir adsorption isothermc)The adsorption varies directly with pressured)The factor 1/n can have values between 0 and 1Correct answer is option 'B'. Can you explain this answer?.

Solutions for A graph is plotted between log (x/m) and P according to the equation x/m = kp1/nWhich of the following statements about this graph is not correct?a)The figure shows Freundlich adsorption isothermb)The figure shows Langmuir adsorption isothermc)The adsorption varies directly with pressured)The factor 1/n can have values between 0 and 1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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