NEET Exam > NEET Questions > In NaCl structure,a)All octahedral and tetrah...
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In NaCl structure,
- a)All octahedral and tetrahedral sites are occupied
- b)Only octahedral sites are occupied
- c)Only tetrahedral sites occupied
- d)Neither octahedral nor tetrahedral sites are occupied
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In NaCl structure,a)All octahedral and tetrahedral sites are occupiedb...
Octahedral sites are occupied by Na+ ions in NaCl structure.
Most Upvoted Answer
In NaCl structure,a)All octahedral and tetrahedral sites are occupiedb...
Explanation:
In the NaCl (sodium chloride) structure, the arrangement of ions is based on a face-centered cubic (FCC) lattice. This means that each ion is surrounded by 6 nearest neighbors arranged in an octahedral configuration.
Octahedral Sites:
The octahedral sites in the NaCl structure are the positions halfway between the ions in the lattice. These sites can accommodate ions of opposite charge. In the case of NaCl, the sodium (Na+) ions occupy the octahedral sites, and the chloride (Cl-) ions occupy the positions in between.
Tetrahedral Sites:
The tetrahedral sites in the NaCl structure are the positions at the center of each face of the cubic lattice. These sites can also accommodate ions of opposite charge. However, in the case of NaCl, the size of the chloride ion is too large to fit into the tetrahedral sites, so these sites remain unoccupied.
Explanation of the Correct Answer:
The correct answer is option 'B' - only octahedral sites are occupied. This is because in the NaCl structure, the larger chloride ions cannot fit into the smaller tetrahedral sites. Therefore, only the octahedral sites are occupied by the smaller sodium ions.
Summary:
In summary, in the NaCl structure, only the octahedral sites are occupied by the smaller sodium ions. The larger chloride ions cannot fit into the tetrahedral sites, so these sites remain unoccupied.
In the NaCl (sodium chloride) structure, the arrangement of ions is based on a face-centered cubic (FCC) lattice. This means that each ion is surrounded by 6 nearest neighbors arranged in an octahedral configuration.
Octahedral Sites:
The octahedral sites in the NaCl structure are the positions halfway between the ions in the lattice. These sites can accommodate ions of opposite charge. In the case of NaCl, the sodium (Na+) ions occupy the octahedral sites, and the chloride (Cl-) ions occupy the positions in between.
Tetrahedral Sites:
The tetrahedral sites in the NaCl structure are the positions at the center of each face of the cubic lattice. These sites can also accommodate ions of opposite charge. However, in the case of NaCl, the size of the chloride ion is too large to fit into the tetrahedral sites, so these sites remain unoccupied.
Explanation of the Correct Answer:
The correct answer is option 'B' - only octahedral sites are occupied. This is because in the NaCl structure, the larger chloride ions cannot fit into the smaller tetrahedral sites. Therefore, only the octahedral sites are occupied by the smaller sodium ions.
Summary:
In summary, in the NaCl structure, only the octahedral sites are occupied by the smaller sodium ions. The larger chloride ions cannot fit into the tetrahedral sites, so these sites remain unoccupied.
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In NaCl structure,a)All octahedral and tetrahedral sites are occupiedb)Only octahedral sites are occupiedc)Only tetrahedral sites occupiedd)Neither octahedral nor tetrahedral sites are occupiedCorrect answer is option 'B'. Can you explain this answer?
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