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Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?
- a)1 L
- b)11.2 L
- c)44 L
- d)22.4 L
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Calcium carbonate decomposes on heating to give calcium oxide and carb...
100 g of CaCO3 at STP gives 22.4 L of CO2
50 g of CaCO3 will produce 22.4/100 x 50 = 11.2 L of CO2
Most Upvoted Answer
Calcium carbonate decomposes on heating to give calcium oxide and carb...
Calculation:
1. Molar mass of CaCO3:
- The molar mass of CaCO3 is 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 * 16.00 g/mol) = 100.09 g/mol
2. Moles of CaCO3:
- Moles = Mass / Molar mass
- Moles = 50 g / 100.09 g/mol = 0.499 moles
3. Volume of CO2:
- According to the balanced chemical equation: CaCO3 → CaO + CO2
- 1 mole of CaCO3 produces 1 mole of CO2
- Volume of 1 mole of any gas at STP (Standard Temperature and Pressure) is 22.4 L
- Therefore, 0.499 moles of CaCO3 will produce 0.499 moles of CO2
- Volume of CO2 = 0.499 moles * 22.4 L/mole = 11.192 L
Answer:
The volume of CO2 obtained by thermal decomposition of 50 g of CaCO3 is 11.2 L. Therefore, the correct answer is option B.
1. Molar mass of CaCO3:
- The molar mass of CaCO3 is 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 * 16.00 g/mol) = 100.09 g/mol
2. Moles of CaCO3:
- Moles = Mass / Molar mass
- Moles = 50 g / 100.09 g/mol = 0.499 moles
3. Volume of CO2:
- According to the balanced chemical equation: CaCO3 → CaO + CO2
- 1 mole of CaCO3 produces 1 mole of CO2
- Volume of 1 mole of any gas at STP (Standard Temperature and Pressure) is 22.4 L
- Therefore, 0.499 moles of CaCO3 will produce 0.499 moles of CO2
- Volume of CO2 = 0.499 moles * 22.4 L/mole = 11.192 L
Answer:
The volume of CO2 obtained by thermal decomposition of 50 g of CaCO3 is 11.2 L. Therefore, the correct answer is option B.
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Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?a)1 Lb)11.2 Lc)44 Ld)22.4 LCorrect answer is option 'B'. Can you explain this answer?
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Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?a)1 Lb)11.2 Lc)44 Ld)22.4 LCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?a)1 Lb)11.2 Lc)44 Ld)22.4 LCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO2 will be obtained by thermal decomposition of 50 g of CaCO3?a)1 Lb)11.2 Lc)44 Ld)22.4 LCorrect answer is option 'B'. Can you explain this answer?.
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