A man driving at 2/3rd of his original speed reaches his destination 3...
Given:
A man driving at 2/3rd of his original speed reaches his destination 30 minutes later than the usual time.
To find:
The usual time taken to reach the destination.
Solution:
Let's assume the usual time taken to reach the destination at the original speed is 'x' minutes.
Step 1: Calculate the time taken at 2/3rd of the original speed
The man is driving at 2/3rd of his original speed, which means he is covering 2/3rd of the distance in the same amount of time it would take him to cover the full distance at his original speed.
So, the time taken at 2/3rd of the original speed = x minutes.
Step 2: Calculate the extra time taken
The man reaches his destination 30 minutes later than the usual time.
So, the extra time taken = 30 minutes.
Step 3: Calculate the distance
We know that speed = distance/time.
Since the man is driving at 2/3rd of his original speed, the speed at which he is driving is (2/3) * original speed.
Let's assume the distance to be 'd'.
So, (2/3) * original speed = d/(x + 30) [Equation 1]
And, original speed = d/x [Equation 2]
Step 4: Equate the distances
Since the distance covered is the same in both cases, we can equate the distances.
d/(x + 30) = d/x
Simplifying this equation, we get:
x + 30 = x
30 = x - x
30 = 0
This is not possible, so our assumption that the man reaches his destination 30 minutes later than the usual time is incorrect.
Conclusion:
There is no valid solution for this problem.