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A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120. If binding energy per nucleon for a parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, then the energy released in the decay is X × 110 MeV. Find the value of X.
  • a)
    200 MeV
  • b)
    -220 MeV
  • c)
    220 MeV
  • d)
    180 MeV
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A heavy nucleus having mass number 200 gets disintegrated into two sma...
Energy released
= (80 × 7 + 120 × 8 – 200 × 6.5)
= 220 MeV
View all questions of this test
Most Upvoted Answer
A heavy nucleus having mass number 200 gets disintegrated into two sma...
The total mass of the nucleus before decay is:

M1 = 200 × 1.6605 × 10^-27 kg/u = 3.321 × 10^-25 kg

The total mass of the two daughter nuclei after decay is:

M2 = (80 × 1.6605 × 10^-27 kg/u) + (120 × 1.6605 × 10^-27 kg/u) = 1.9926 × 10^-25 kg

The mass difference between the two states is:

ΔM = M1 - M2 = 1.3284 × 10^-25 kg

Using Einstein's famous formula E = mc^2, we can calculate the energy released in the decay:

E = ΔM × c^2 = 1.3284 × 10^-25 kg × (3 × 10^8 m/s)^2 = 1.1956 × 10^-8 J

Converting to MeV, we get:

1.1956 × 10^-8 J ÷ 1.6022 × 10^-13 J/MeV = 74.7 MeV

However, we have to take into account the binding energy per nucleon for the parent and daughter nuclei. The total binding energy of the parent nucleus is:

BE1 = 200 × 6.5 MeV = 1300 MeV

The total binding energy of the two daughter nuclei is:

BE2 = (80 × 7 MeV) + (120 × 8 MeV) = 1760 MeV

Therefore, the energy released in the decay is:

X = (BE1 - BE2) + 74.7 MeV = (1300 MeV - 1760 MeV) + 74.7 MeV = -385.3 MeV

The negative sign indicates that energy is released in the decay. The value of X is -385.3 MeV.
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A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120. If binding energy per nucleon for a parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, then the energy released in the decay is X × 110 MeV. Find the value of X.a)200 MeVb)-220 MeVc)220 MeVd)180 MeVCorrect answer is option 'C'. Can you explain this answer?
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