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The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians):
  • a)
    π/6
  • b)
    π/3
  • c)
    π/8
  • d)
    π/4
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about th...
Torque about the origin =
= r F sin θ ⇒ 2.5 = 1 × 5 sin θ
sin θ = 0.5 = 1/2
⇒ θ = π/6
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The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians):a)π/6b)π/3c)π/8d)π/4Correct answer is option 'A'. Can you explain this answer?
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