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An electron is constrained to move along the y axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m. The maximum magnetic force experienced by the electron will be :
(given c = 3 × 108 ms–1 & electron charge = 1.6 × 10–19C)
  • a)
    3.2 × 10–18 N
  • b)
    2.4 × 10–18 N
  • c)
    4.8 × 10–19 N
  • d)
    1.6 × 10–19 N
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An electron is constrained to move along the y axis with a speed of 0...
In electromagnetic wave, E0/B0 = C
∴ Maximum value of magnetic field, B0 = E0/C
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Most Upvoted Answer
An electron is constrained to move along the y axis with a speed of 0...
To find the maximum magnetic force experienced by the electron, we first need to calculate the maximum magnetic field (B) experienced by the electron.

The magnetic field (B) is related to the electric field (E) by the equation:

B = E/c

where c is the speed of light.

Given that E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m and c = 3 × 108 m/s, we can substitute these values into the equation to find B:

B = (30J sin(1.5 × 107t – 5 × 10–2x))/ (3 × 108 m/s)

Now we need to find the maximum value of sin(1.5 × 107t – 5 × 10–2x). The maximum value of sin(x) is 1, so we can substitute this value into the equation to find the maximum magnetic field:

B_max = (30J * 1)/ (3 × 108 m/s)

B_max = 0.1 J/ (3 × 108 m/s)

Now we can calculate the maximum magnetic force (F) experienced by the electron using the equation:

F = qvB

where q is the charge of the electron and v is its velocity.

Given that the speed of the electron is 0.1c, we can substitute the values into the equation to find the maximum magnetic force:

F = (1.6 × 10^-19 C) * (0.1c) * (0.1 J/ (3 × 108 m/s))

F = (1.6 × 10^-19 C) * (0.1 * 3 × 10^8 m/s) * (0.1 J/ (3 × 108 m/s))

F = 1.6 × 10^-20 J

Therefore, the maximum magnetic force experienced by the electron will be 1.6 × 10^-20 J.
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An electron is constrained to move along the y axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m. The maximum magnetic force experienced by the electron will be :(given c = 3 × 108 ms–1 & electron charge = 1.6 × 10–19C)a)3.2 × 10–18 Nb)2.4 × 10–18 Nc)4.8 × 10–19 Nd)1.6 × 10–19 NCorrect answer is option 'C'. Can you explain this answer?
Question Description
An electron is constrained to move along the y axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m. The maximum magnetic force experienced by the electron will be :(given c = 3 × 108 ms–1 & electron charge = 1.6 × 10–19C)a)3.2 × 10–18 Nb)2.4 × 10–18 Nc)4.8 × 10–19 Nd)1.6 × 10–19 NCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron is constrained to move along the y axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m. The maximum magnetic force experienced by the electron will be :(given c = 3 × 108 ms–1 & electron charge = 1.6 × 10–19C)a)3.2 × 10–18 Nb)2.4 × 10–18 Nc)4.8 × 10–19 Nd)1.6 × 10–19 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron is constrained to move along the y axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E = 30J sin(1.5 × 107t – 5 × 10–2x) V/m. The maximum magnetic force experienced by the electron will be :(given c = 3 × 108 ms–1 & electron charge = 1.6 × 10–19C)a)3.2 × 10–18 Nb)2.4 × 10–18 Nc)4.8 × 10–19 Nd)1.6 × 10–19 NCorrect answer is option 'C'. Can you explain this answer?.
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