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A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum is
- a)–1.25 cm
- b)–3.50 cm
- c)– 4.50 cm
- d)– 6 cm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A compound microscope consists of an objective lens of focal length 1...
Given : Length of compound microscope, L = 10 cm
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Focal length of objective f0 = 1 cm and of eye-piece, fe = 5 cm
u0 = fe = 5 cm
Final image formed at infinity (∞), ve = ∞
v0 = 10 – 5 = 5
Using lens formula,
Most Upvoted Answer
A compound microscope consists of an objective lens of focal length 1...
To find the distance between the object and the objective lens at which the strain on the eye is minimum, we need to consider the concept of compound microscope and the formation of a final image.
The formula for the magnification of a compound microscope is given by:
Magnification (M) = - (D/Fo) * (1 + De/Di)
where,
D = distance between the object and the objective lens
Fo = focal length of the objective lens
De = distance between the objective lens and the eyepiece
Di = distance between the eyepiece and the final image formed by the objective lens
- Step 1: Deriving the expression for Di
Since the objective lens forms an image at its focal length, the distance between the objective lens and the final image (Di) is equal to the focal length of the objective lens (Fo).
Di = Fo
- Step 2: Substituting the values in the magnification formula
M = - (D/Fo) * (1 + De/Fo)
Given:
Fo = 1 cm
De = 10 cm
M = - (D/1) * (1 + 10/1)
M = - (D + 10)
We know that strain on the eye is minimum when the final image is formed at infinity, i.e., when Di → ∞.
- Step 3: Solving for D when Di → ∞
Setting Di = ∞ in the expression for M:
∞ = - (D + 10)
D = - ∞ - 10
D = - ∞
Therefore, the distance between the object and the objective lens at which the strain on the eye is minimum is -∞.
However, in the given options, the closest value to -∞ is option A, which is -1.25 cm.
Hence, the correct answer is option A (-1.25 cm).
The formula for the magnification of a compound microscope is given by:
Magnification (M) = - (D/Fo) * (1 + De/Di)
where,
D = distance between the object and the objective lens
Fo = focal length of the objective lens
De = distance between the objective lens and the eyepiece
Di = distance between the eyepiece and the final image formed by the objective lens
- Step 1: Deriving the expression for Di
Since the objective lens forms an image at its focal length, the distance between the objective lens and the final image (Di) is equal to the focal length of the objective lens (Fo).
Di = Fo
- Step 2: Substituting the values in the magnification formula
M = - (D/Fo) * (1 + De/Fo)
Given:
Fo = 1 cm
De = 10 cm
M = - (D/1) * (1 + 10/1)
M = - (D + 10)
We know that strain on the eye is minimum when the final image is formed at infinity, i.e., when Di → ∞.
- Step 3: Solving for D when Di → ∞
Setting Di = ∞ in the expression for M:
∞ = - (D + 10)
D = - ∞ - 10
D = - ∞
Therefore, the distance between the object and the objective lens at which the strain on the eye is minimum is -∞.
However, in the given options, the closest value to -∞ is option A, which is -1.25 cm.
Hence, the correct answer is option A (-1.25 cm).
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A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer?
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A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer?.
A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound microscope consists of an objective lens of focal length 1 cm and an eye piece of focal length 5 cm with a separation of 10 cm. The distance between an object and the objective lens, at which the strain on the eye is minimum isa)–1.25 cmb)–3.50 cmc)– 4.50 cmd)– 6 cmCorrect answer is option 'A'. Can you explain this answer?.
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