NEET Exam  >  NEET Questions  >   A ray of light is incident from a denser to ... Start Learning for Free
A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:
  • a)
    0.2
  • b)
    0.4
  • c)
    0.8
  • d)
    0.9
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A ray of light is incident from a denser to a rarer medium. The criti...
To find the relative refractive index of the two media, we need to use the given information about the critical angle and Brewster's angle.

1. Critical Angle (θiC):
The critical angle is the angle of incidence at which the refracted ray is at an angle of 90 degrees to the normal. It occurs when the angle of refraction is 90 degrees, which means the refracted ray is parallel to the boundary between the two media.

2. Brewster's Angle (θiB):
Brewster's angle is the angle of incidence at which the reflected and refracted rays are perpendicular to each other. It occurs when the reflected ray is completely polarized and the reflected and refracted rays are at right angles to each other.

Given: sin(θiB) = η = 1.28

3. Relationship between Critical Angle and Refractive Index:
The critical angle is related to the refractive index by the equation: sin(θiC) = 1/η

Now, let's solve for the relative refractive index:

sin(θiC) = 1/η
sin(θiC) = 1/1.28
sin(θiC) = 0.78125

Taking the inverse sine of both sides, we find:

θiC = sin^(-1)(0.78125)
θiC ≈ 51.06 degrees

4. Relationship between Brewster's Angle and Refractive Index:
Brewster's angle is related to the refractive index by the equation: tan(θiB) = η

Given: sin(θiB) = η = 1.28

Let's solve for θiB:

sin(θiB) = 1.28
θiB = sin^(-1)(1.28)
θiB ≈ 51.72 degrees

5. Relative Refractive Index (η):
The relative refractive index can be calculated by taking the tangent of Brewster's angle:

tan(θiB) = η
tan(51.72) = η
η ≈ 1.28

Therefore, the relative refractive index of the two media is approximately 1.28, which corresponds to option 'C' in the given choices.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
Explore Courses for NEET exam

Top Courses for NEET

A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer?
Question Description
A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer?.
Solutions for A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is θiC and Brewster’s angle of incidence is θiB, such that sin x/sin θiB = η = 1.28. The relative refractive index of the two media is:a)0.2b)0.4c)0.8d)0.9Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
Explore Courses for NEET exam

Top Courses for NEET

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev