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At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g) ⇌ H2(g) + I2(g). The equilibrium constant for this reaction is:a)0.25b)1.0c)3.0d)0.5Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g) ⇌ H2(g) + I2(g). The equilibrium constant for this reaction is:a)0.25b)1.0c)3.0d)0.5Correct answer is option 'A'. Can you explain this answer?, a detailed solution for At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g) ⇌ H2(g) + I2(g). The equilibrium constant for this reaction is:a)0.25b)1.0c)3.0d)0.5Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g) ⇌ H2(g) + I2(g). The equilibrium constant for this reaction is:a)0.25b)1.0c)3.0d)0.5Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice At a certain temperature, only 50% HI is dissociated at equilibrium in the following reaction: 2HI(g) ⇌ H2(g) + I2(g). The equilibrium constant for this reaction is:a)0.25b)1.0c)3.0d)0.5Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.