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An object is projected with a velocity of 20 m/s making an angle of 45° horizontally. The equation for the trajectory is h = Ax – Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms–2)
  • a)
    1 : 5
  • b)
    5 : 1
  • c)
    1 : 40
  • d)
    40 : 1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
An object is projected with a velocity of 20 m/s making an angle of 4...
Standard equation of projectile motion
Comparing with given equation
(As θ = 45°, u = 20 m/s, g = 10 m/s2)
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Community Answer
An object is projected with a velocity of 20 m/s making an angle of 4...
Standard equation of projectile motion
Comparing with given equation
(As θ = 45°, u = 20 m/s, g = 10 m/s2)
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An object is projected with a velocity of 20 m/s making an angle of 45° horizontally. The equation for the trajectory is h = Ax – Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms–2)a)1 : 5b)5 : 1c)1 : 40d)40 : 1Correct answer is option 'D'. Can you explain this answer?
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An object is projected with a velocity of 20 m/s making an angle of 45° horizontally. The equation for the trajectory is h = Ax – Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms–2)a)1 : 5b)5 : 1c)1 : 40d)40 : 1Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An object is projected with a velocity of 20 m/s making an angle of 45° horizontally. The equation for the trajectory is h = Ax – Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms–2)a)1 : 5b)5 : 1c)1 : 40d)40 : 1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is projected with a velocity of 20 m/s making an angle of 45° horizontally. The equation for the trajectory is h = Ax – Bx2 where h is height, x is horizontal distance, A and B are constants. The ratio A : B is (g = 10 ms–2)a)1 : 5b)5 : 1c)1 : 40d)40 : 1Correct answer is option 'D'. Can you explain this answer?.
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