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If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I?
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If intensity of each of the two waves is I and they are having phase d...
Given:
- Intensity of each wave = I
- Phase difference between the waves = 120 degrees
To find:
Resultant intensity when the waves are superimposed
Solution:
When two waves superimpose, the resultant intensity is given by the formula:
I(resultant) = I1 + I2 + 2√(I1 * I2) * cos(ϕ)
Where:
- I1 and I2 are the intensities of the individual waves
- ϕ is the phase difference between the waves
Substituting the given values:
- I1 = I
- I2 = I
- ϕ = 120 degrees
Calculating the Resultant Intensity:
I(resultant) = I + I + 2√(I * I) * cos(120)
Simplifying the equation:
I(resultant) = 2I + 2√(I^2) * cos(120)
I(resultant) = 2I + 2I * cos(120)
Using the trigonometric identity, cos(120) = -0.5:
I(resultant) = 2I + 2I * (-0.5)
I(resultant) = 2I - I
I(resultant) = I
Answer:
The resultant intensity when the waves are superimposed is I. Therefore, the correct option is a- I.
- Intensity of each wave = I
- Phase difference between the waves = 120 degrees
To find:
Resultant intensity when the waves are superimposed
Solution:
When two waves superimpose, the resultant intensity is given by the formula:
I(resultant) = I1 + I2 + 2√(I1 * I2) * cos(ϕ)
Where:
- I1 and I2 are the intensities of the individual waves
- ϕ is the phase difference between the waves
Substituting the given values:
- I1 = I
- I2 = I
- ϕ = 120 degrees
Calculating the Resultant Intensity:
I(resultant) = I + I + 2√(I * I) * cos(120)
Simplifying the equation:
I(resultant) = 2I + 2√(I^2) * cos(120)
I(resultant) = 2I + 2I * cos(120)
Using the trigonometric identity, cos(120) = -0.5:
I(resultant) = 2I + 2I * (-0.5)
I(resultant) = 2I - I
I(resultant) = I
Answer:
The resultant intensity when the waves are superimposed is I. Therefore, the correct option is a- I.
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If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I?
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If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I?.
If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If intensity of each of the two waves is I and they are having phase difference of 120 degree, when the waves are superimposed, then the resultant intensity will be? a- I b- 2I c - I/2 d- 4I?.
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